比较Django 2中间件中的url路径

问题描述 投票:0回答:1

我需要开发一个Django中间件并创建这样的类:

import re
from django.conf import settings
from django.shortcuts import redirect
from django.contrib.auth import logout


class LoginRequiredMiddleware:

    def __init__(self, get_response):
        self.get_response = get_response

    def __call__(self, request):
        response = self.get_response(request)
        return response

    def process_view(self, request, view_func, view_args, view_kwargs):
        assert hasattr(request, 'user')

        path = request.path_info
        print(path)

        p = path.lstrip('/')
        compiled_login_url = re.compile(settings.LOGIN_URL)

        print(compiled_login_url.match(p))


        if not request.user.is_authenticated:
            if path == '/':
                print("==============> INDEX PAGE")

现在,我想比较网址的路径。我必须确定路径是否与settings.LOGIN_URL匹配。我尝试过使用正则表达式,但他们没有帮助。

这是我的网址

urlpatterns = [
              path('admin/', admin.site.urls),
              path('', views.index, name='index'),
              path('<slug:slug>/', include('app.urls')),
              path('<slug:slug>/accounts/login/', views.login, name='login'),
              path('<slug:slug>/accounts/logout/', views.logout, name='logout'),
              path('<slug:slug>/dashboard/', 'views.dashboard', name='dashboard'),
          ] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

我想免除登录和注销中间件检查我也需要slug。

views.朋友

def user_login(request, slug):
    """
    Login user using email and password

    :param request: WSGI Request
    :param slug: to verify the facility
    :return: login page or redirect
    """

    context = {}
    try:
        facility = models.Facility.objects.get(slug=slug)
        context['facility'] = facility

    except models.Facility.DoesNotExist:
        return redirect('index')

    if request.method == "POST":
        email = request.POST['email']
        password = request.POST['password']

        user = authenticate(request, username=email, password=password)
        if user is not None:
            if user.profile.facility.slug == slug:
                login(request, user)
                return redirect('dashboard', slug=slug)
            else:
                context['error'] = "You don't belong to this facility"

        else:
            context['error'] = "Invalid email or password"

    return render(request, 'app/user/login.html', context)


@login_required
def dashboard(request, slug):
    """
    Display the dashboard of facility and list down bird
    view for the daily, weekly, monthly and yearly progress

    :param request:
    :return:
    """
    context = {}

    try:
        facility = models.Facility.objects.get(slug=slug)
        context['facility'] = facility
    except models.Facility.DoesNotExist:
        return render(request, 'app/404.html', status=404)

的index.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
</head>
<body>
<ul>
    {% for f in facilities %}
        <li><a href="{% url 'login' f.slug %}">{{ f.name }}</a></li>
    {% empty %}
        <li>No Facility</li>
    {% endfor %}
</ul>
</body>
</html>
python django url middleware
1个回答
0
投票

你可以将Django的auth视图逐个添加到你的urlpatterns,用login_exempt装饰每个。

OR

如果您想将检查移动到中间件,您可以尝试以下方法:

urls.py

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include("myapp.urls")),
    path('accounts/', include('django.contrib.auth.urls', namespace="accounts"))
] 

middleware.py

class LoginRequiredMiddleware:            # <-- Custom Middleware
    def __init__(self, get_response):
        self.get_response = get_response

    def __call__(self, request):
        return self.get_response(request)

    def process_view(self, request, view_func, view_args, view_kwargs):

        if getattr(view_func, 'login_exempt', False):
            return

        if 'accounts' in request.resolver_match.namespaces:
            return

其他可能性可能是检查中间件中的URL或视图名称,但仍然可能是最干净的将使用您的装饰器并逐个添加必要的视图。

OR

你可以使用django-decorator-include

$ pip install django-decorator-include

在你project/url.py

from decorator_include import decorator_include
from project/custom_middleware import login_exempt


urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include("myapp.urls")),
    # do this 
    path('accounts/', decorator_include(login_exempt, 'django.contrib.auth.urls'))


]

不要忘记在requirements.txt中添加包

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