XML到数据帧解析时重复值

Question

该代码的目的是从xml文件中获取元素并将其解析为csv文件。

最近我已经更新了代码，所以代码转到了[[Phones（ProjectData的另一个子代），它从Set中获取元素，并且Get将它们与下划线附加在一起，并将其解析为第一列标题名称为Identify这是我的代码

from xml.etree import ElementTree as ET
from collections import defaultdict
from pathlib import Path
import csv
from pathlib import Path


directory = 'C:/Users/TRY/try.xml'

with open('try.csv', 'w', newline='') as f:
    writer = csv.writer(f, delimiter=';')
   #◙ writer = csv.writer(f)

    headers = ['identify','id', 'service_code', 'rational', 'qualify', 'description_num', 'description_txt','Counter', 'set_data_xin', 'set_data_xax', 'set_data_value', 'set_data_x']

    writer.writerow(headers)

    xml_files_list = list(map(str,Path(directory).glob('**/*.xml')))
    for xml_file in xml_files_list:
        tree = ET.parse(xml_file)
        root = tree.getroot()
        p_get = tree.find('.//Phones/Get').text
        p_set = tree.find('.//Phones/Set').text


        start_nodes = root.findall('.//START')
        for sn in start_nodes:
            row = defaultdict(str)

            # <<<<< Indentation was wrong here
            for k,v in sn.attrib.items():
                row[k] = v
            for rn in sn.findall('.//Rational'):
                row['Rational'] = rn.text

            for qu in sn.findall('.//Qualify'):
                row['Qualify'] = qu.text

            for ds in sn.findall('.//Description'):
                row['Description_txt'] = ds.text
                row['Description_text_id'] = ds.attrib['text_id']



            for counter, st in enumerate( sn.findall('.//SetData') ):
                for k,v in st.attrib.items():
                    if v.startswith("-"):
                        v = v.replace("-","",1)
                    v=v.replace(',', '.')
                    row['SetData_'+ str(k)] = v
                row["Counter"] = counter 
                row_data = [row[i] for i in headers]
                row_data[0]=p_get + '_' + p_set
                writer.writerow(row_data)
                row = defaultdict(str)

这是xml文件
<?xml version="1.0" encoding="utf-8"?>
<ProjectData>
 <Phones>
    <Date />
    <Prog />
    <Box />
    <Feature />
    <IN>MAFWDS</IN>
    <Set>234234</Set>
    <Pr>23423</Pr>
    <Number>afasfhrtv</Number>
    <Simple>dfasd</Simple>
    <Nr />
    <Get>6070106091</Get>
    <Reno>1233</Reno>
  </Phones>
<FINAL>
    <START id="B001" service_code="0x5196">
      <Docs Docs_type="START">
        <Rational>225196</Rational>
        <Qualify>6251960000A0DE</Qualify>
      </Docs>
      <Description num="1213f2312">The parameter</Description>
      <DataFile dg="12" dg_id="let">
        <SetData value="32" />
      </DataFile>
    </START>
    <START id="C003" service_code="0x517B">
      <Docs Docs_type="START">
        <Rational>23423</Rational>
        <Qualify>342342</Qualify>
      </Docs>
      <Description num="3423423f3423">The third</Description>
      <DataFile dg="55" dg_id="big">
        <SetData x="E1" value="21259" />
        <SetData x="E2" value="02" />
      </DataFile>
    </START>
    <START id="Z048" service_code="0x5198">
      <RawData rawdata_type="ASDS">
        <Rational>225198</Rational>
        <Qualify>3432433</Qualify>
      </RawData>
      <Description num="434234234">The forth</Description>
      <DataFile unit="21" unit_id="FEDS">
        <FileX unit="eg" discrete="false" axis_pts="19" name="Vsome" text_id="bx5" unit_id="GDFSD" />
        <SetData xin="5" xax="233" value="323" />
        <SetData xin="123" xax="77" value="555" />
        <SetData xin="17" xax="65" value="23" />
      </DataFile>
    </START>
</FINAL>
</ProjectData>

输出看起来像这样，应该看起来像。
问题是列[[identify

被重复。我想要，所以不再重复。我尝试使用该代码，并在代码中移动此变量，但没有成功，由于列是由xml文件的另一个子元素组成的，因此很难解决此问题。

Answer 1

如果您希望每个原始行仅看到一次，则必须在内部循环row之前直接在for counter, st in enumerate( sn.findall('.//SetData') ):中进行设置>

例如：

        row['identify']=p_get + '_' + p_set
        for counter, st in enumerate( sn.findall('.//SetData') ):
            for k,v in st.attrib.items():
                if v.startswith("-"):
                    v = v.replace("-","",1)
                v=v.replace(',', '.')
                row['SetData_'+ str(k)] = v
            row["Counter"] = counter 
            row_data = [row[i] for i in headers]
            writer.writerow(row_data)
            row = defaultdict(str)