按类INSTAGRAM复制标题,selenium python

问题描述 投票:0回答:1

伙计们,我想要追随者Instagram的复制昵称。

这是我的代码,但不起作用:

browser = webdriver.Chrome('./chromedriver')

"GO INSTAGRAM PAGE FOR LOGIN"

browser.get('https://www.instagram.com/accounts/login/?hl=it')

sleep(2)

"ID AND PASSWORD"

elem = browser.find_element_by_name("username").send_keys('test')

elem = browser.find_element_by_name("password").send_keys('pswtest')

"CLICK BUTTON AND OPEN INSTAGRAM"
sleep(5)
good_elem = browser.find_element_by_xpath('//*[@id="react-root"]/section/main/div/article/div/div[1]/div/form/span/button').click()

sleep(5)

browser.get("https://www.instagram.com")

sleep(2)

browser.get("https://www.instagram.com/test/")
sleep(10)

copy = browser.find_element_by_class_name('FPmhX notranslate zsYNt').Text

这是Instagram:

"
a class="FPmhX notranslate zsYNt " title="s_yagami_" href="/s_yagami_/">s_yagami_ a"

我想复制标题,帮帮我。

python selenium selenium-webdriver instagram
1个回答
1
投票

title<a>标签的属性,所以可以尝试:

copy = browser.find_element_by_class_name('FPmhX notranslate zsYNt')
copy.get_attribute("title")
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