Arduino TFT 触摸扩展板:循环绘制

问题描述 投票:0回答:1

我正在尝试用 TFT 触摸板构建一个菜单。现在我的问题是我无法在循环函数中绘制任何内容。

如果我在循环中编写任何绘图函数,屏幕就会变成白色。我认为这是因为屏幕需要一些时间来建立。所以我添加了一个延迟(1000)。但屏幕每秒都会闪烁,这显然也不是我想要的。

下一个奇怪的事情是,当我触摸显示器后进行绘制时,程序停止工作。在下面的代码中我有三个绘图函数。其中两个在工作,一个不在。 (见评论)

#include <SeeedTouchScreen.h>

#include <TFTConsole.h>
#include <Adafruit_TFTLCD.h>
#include <Adafruit_GFX.h>


#define LCD_CS A3
#define LCD_CD A2
#define LCD_WR A1
#define LCD_RD A0
#define LCD_RESET A4

#define TS_MINX 169
#define TS_MINY 208
#define TS_MAXX 1781
#define TS_MAXY 1820

#define YP A2  // must be an analog pin, use "An" notation!
#define XM A3  // must be an analog pin, use "An" notation!
#define YM 8   // can be a digital pin
#define XP 9   // can be a digital pin

#define BLACK   0x0000
#define BLUE    0x001F
#define RED     0xF800
#define GREEN   0x07E0
#define CYAN    0x07FF
#define MAGENTA 0xF81F
#define YELLOW  0xFFE0
#define WHITE   0xFFFF

Adafruit_TFTLCD tft(LCD_CS, LCD_CD, LCD_WR, LCD_RD, LCD_RESET);
TouchScreen ts = TouchScreen(XP, YP, XM, YM);
boolean touched = false;


void setup() {
  Serial.begin(9600);
  Serial.print("Starting...");

  tft.reset();

  tft.begin(0x9325);

  tft.setRotation(1);

  tft.fillScreen(BLACK);

  //Print "PPM CO" Text
  tft.setCursor(50, 30);
  tft.setTextColor(GREEN);
  tft.setTextSize(3);
  tft.print("Hello World"); //<- this is displayed fine
  delay(1000);
}
boolean first = true;
void loop() {
  if (first) {
    first = false;
    tft.drawCircle(119, 160, 20, random(0xFFFF)); //<- This is also displayed
  }


  Point p = ts.getPoint();


  p.x = map(p.x, TS_MINX, TS_MAXX, 0, 240);
  p.y = map(p.y, TS_MINY, TS_MAXY, 0, 320);
  if (p.x <= 240 && p.y <= 320 && p.x >= 0 && p.y >= 0) {
    Serial.println("don't touch me!");
    touched = true;
  }
  else {
    touched = false;
  }
  if (touched) {

    tft.drawCircle(119, 180, 20, RED); //<- This is not displayed and makes the screen flash
    delay(1000);
  }


  //tft.fillScreen(BLUE);
  //delay(500);

}

只有当我在代码中有最后一个drawCircle时,如果我停止触摸显示屏,变量touched不会切换回false。

有人知道我做错了什么吗?

更新:我通过让触摸事件仅在触摸显示屏时发生一次来阻止显示屏闪烁。但我仍然遇到什么都没有绘制的问题...

void loop() {
  //Touchposition bestimmen
  Point p = ts.getPoint();
  p.x = map(p.x, TS_MINX, TS_MAXX, 0, 240);
  p.y = map(p.y, TS_MINY, TS_MAXY, 0, 320);
  if (p.x <= 240 && p.y <= 320 && p.x >= 0 && p.y >= 0) {
    if (released) {
      touched = true;
      released = false;
    }
  }
  else {
    //Serial.println("Touch me where I like it!");
    touched = false;
    released = true;
  }
  if (touched && !released) {
    Serial.println("don't touch me!");
    drawButton(100, 100, "Manuell");
    touched = false;
    delay(500);
  }
}
c++ arduino-uno touchscreen
1个回答
1
投票

我注意到 TFT 显示屏和触摸屏共享一些模拟引脚。我认为这是造成问题的原因。 因此,我将代码分为处理触摸屏的部分。然后我可以将引脚重新分配给 TFT 显示器并对其进行绘制。我不知道这个理论是否有意义,但它确实有效:

 void loop() {
  //Touchposition bestimmen
  if (ts.isTouching()) {
    Point p = ts.getPoint();
    p.x = map(p.x, TS_MINX, TS_MAXX, 0, 240);
    p.y = map(p.x, TS_MINY, TS_MAXY, 0, 320);
    if (released) {
      released = false;
    }
  }
  else {
    //Serial.println("Touch me where I like it!");
    released = true;
  }

  if (ts.isTouching() && !released) {
    //re assing pins to tft because they are also used by the touchscreen
    Adafruit_TFTLCD tft(LCD_CS, LCD_CD, LCD_WR, LCD_RD, LCD_RESET);
    Serial.println("don't touch me!");
    drawButton(100, 100, "Manuell");
    touched = false;
  }
}

drawButton funton 包含多个绘制函数

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