累计金额和百分比

问题描述 投票:3回答:2

我有一个名为Sales的表:

id_sale  id_ticket  total  state
-------  ---------  -----  -----
100      100        30     inactive    
101      101        30     active    
102      101        60     active    
103      102        30     active    
104      102        30     active    
105      103        10     active    
106      103        5      active    

我需要的是得到total列的总和,当状态处于活动状态时的总和(总计)并将其乘以x百分比(我可以这样做),因为我必须选择他们总和的所有门票(所有票据总结)是<= sum(total) * x percentage并将其复制到另一个表(相同的值)

因此,如果我有票101 = 90和票102的总和= 60和票103的总和= 15,总和(总)* x百分比= 160,查询将只返回来自的所有信息票101和102。

整个上午阅读我找到了一个代码,它以某种方式做了我需要的东西,但使用id_Sales而不是id_ticket:

    select t1.id_sale, t1.total, SUM(t2.total) as sum
    from sales t1
    inner join sales t2 on t1.id_sale >= t2.id_sale
    where t2.state='active'
    group by t1.id_sale, t1.total
    having sum(t2.total)<=(
                           select sum(total)*.65
                           from sales
                           where state='active')
    order by t1.id_sale

我期望收到的是:

id_sale  id_ticket  total  state
-------  ---------  -----  ----- 
101      101        30     active    
102      101        60     active    
103      102        30     active    
104      102        30     active

票据101和票102的总和是<=总和(总)* x

所以总和101和102 = 150和总和(总)* x = 160(例如)

我怎样才能做我需要的或如何编辑这些代码,以便它能够满足我的需求。

sql-server sql-server-2005 sum
2个回答
1
投票

你可以从这样的事情开始:

WITH grouped_and_ranked AS (
  SELECT
    id_ticket,
    ticket_total = SUM(total),
    grand_total = SUM(SUM(total)) OVER (),
    ticket_rnk = ROW_NUMBER() OVER (ORDER BY id_ticket)
  FROM sales
  WHERE state = 'active'
  GROUP BY id_ticket
),
cumulative AS (
  SELECT
    id_ticket,
    ticket_total,
    grand_total,
    ticket_rnk,
    total_so_far = ticket_total
  FROM grouped_and_ranked
  WHERE ticket_rnk = 1
  UNION ALL
  SELECT
    r.id_ticket,
    r.ticket_total,
    r.grand_total,
    r.ticket_rnk,
    total_so_far = c.total_so_far + r.ticket_total 
  FROM grouped_and_ranked r
    INNER JOIN cumulative c ON r.ticket_rnk = c.ticket_rnk + 1
  WHERE r.ticket_total columns
)
SELECT
  s.id_sale,
  s.id_ticket,
  s.total,
  s.state
FROM sales s
INNER JOIN cumulative c ON s.id_ticket = c.id_ticket
;

第一个CTEgrouped_and_ranked,检索活跃的销售额并按票数和总计计算总数(使用windowed SUM())。它还将排名编号分配给稍后在计算运行总计时使用的故障单。

下一个CTE,cumulative,是一个递归CTE。只要运行总数不大于总计的指定@percent'age,它就从前一个结果集中检索行。

主SELECT使用最终票证列表来获取详细信息行,方法是将列表连接回sales表。

这个查询可以测试at SQL Fiddle


1
投票

这可以通过仅使用窗口函数相对容易地完成,而不需要递归。

select id_sale, id_ticket, total, state
from (
  select
    id_sale, id_ticket, total, state,

    -- Now we can calculate the cumulative percentage easily
    sum(sum_per_ticket) over (order by id_sale) / sum(sum_per_ticket) over () percentage
  from (
    select
      id_sale, id_ticket, total, state,

      -- Calculate the sum per ticket and place it only on the first row per id_ticket
      -- Fill the other rows with nulls.
      case when id_sale = 
                first_value(id_sale) over (partition by id_ticket order by id_sale) 
           then sum(total) over (partition by id_ticket) end sum_per_ticket
    from sales
    where state = 'active'
  ) t
) t
where percentage <= 0.65
order by id_sale

I have blogged about calculating cumulative percentages in more detail here

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