如何使用属性添加Hibernate的HQL / SQL的结果（列表）来的JavaFX的TableView（ObservableList）？

Question

我使用休眠5.0.7和JavaFX对于UI's.I从数据库中获得的数据列表，我想向他们展示在的tableView，但在所示的tableView没有的事。

这里是表结构

CREATE TABLE product
(
    idproduct serial NOT NULL,
    namefr character varying(50),
    qtyinhand double precision,
    sellprice double precision,
    CONSTRAINT product_pkey PRIMARY KEY(idproduct)
)

对象关系映射：

package model;

@Entity
@Table(name = "Product")
@Access(AccessType.PROPERTY)
public class Product {
    private LongProperty idProduct;
    private StringProperty nameFr;
    private DoubleProperty qtyInHand;
    private DoubleProperty sellPrice;


    public Product() {
        idProduct = new SimpleLongProperty();
        nameFr = new SimpleStringProperty();
        qtyInHand = new SimpleDoubleProperty();
        sellPrice = new SimpleDoubleProperty();

    }

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "product_seq_gen")
    @SequenceGenerator(name = "product_seq_gen", sequenceName = "product_idproduct_seq")
    @Column(name = "idproduct", unique = true, nullable = false)
    public Long getIdProduct() {
        return idProduct.get();
    }

    public LongProperty idProductProperty() {
        return idProduct;
    }

    public void setIdProduct(Long idProduct) {
        this.idProduct.set(idProduct);
    }

    @Column(name = "nameFr")
    public String getNameFr() {
        return nameFr.get();
    }

    public StringProperty nameFrProperty() {
        return nameFr;
    }

    public void setNameFr(String nameFr) {
        this.nameFr.set(nameFr);
    }

    @Column(name = "qtyInHand")
    public double getQtyInHand() {
        return qtyInHand.get();
    }

    public DoubleProperty qtyInHandProperty() {
        return qtyInHand;
    }

    public void setQtyInHand(double qtyInHand) {
        this.qtyInHand.set(qtyInHand);
    }

    @Column(name = "sellPrice")
    public double getSellPrice() {
        return sellPrice.get();
    }

    public DoubleProperty sellPriceProperty() {
        return sellPrice;
    }

    public void setSellPrice(double sellPrice) {
        this.sellPrice.set(sellPrice);
    }
}

我使用Hibernate来检索从数据库产品列表：

public ObservableList<Product> findAll() {

    try {

        session.beginTransaction();
        Query query = session.createSQLQuery("select * from product");
        ObservableList<Product> list = FXCollections.observableArrayList(query.list());

        session.getTransaction().commit();
        session.close();
        return list;
    } catch (Exception e) {
        e.printStackTrace();
        return null;
    }
}

从那以后，我设置表格视图来显示数据：

tcID.setCellValueFactory(new PropertyValueFactory<Product, Long>("idProduct"));
tcNameFR.setCellValueFactory(new PropertyValueFactory("nameFr"));
tcQtyInHand.setCellValueFactory(new PropertyValueFactory("qtyInHand"));
tcSellPrice.setCellValueFactory(new PropertyValueFactory<Product, Double>("sellPrice"));

ProductDAO dao=new ProductDAO();
tableView.getItems().addAll(dao.findAll());

从那以后，我不能得到实现代码如下所示的项目，而不是当我调试我注意到dao.findAll（）返回大小> 0列表，但表不显示任何东西。

Answer 1

由于您使用的是SQL查询，Hibernate不知道你的实体与查询相关联。你可以做

SQLQuery query = session.createSQLQuery("select * from product");
query.addEntity(Product.class);
ObservableList<Product> list = FXCollections.observableArrayList(query.list());

它可能会更好，虽然使用HQL查询：

// the really concise, but not very readable "from Product" works as the query too
Query query = session.createQuery("select p from Product as p");
ObservableList<Product> list = FXCollections.observableArrayList(query.list());