Swift。如何设置自定义数字格式？带空格thouthand分隔符，并在点后>两位[]

Question

我需要用空格隔开的thouthand，点后两位。

let d1: Double = 20000000.0
let d2: Double = 1.2345

我想查看：

let s1 = String(format: "????", d1) //20 000 000.00
let s2 = String(format: "????", d2) //1.23

如何做？

我需要分开的thouthands，它们之间有空格，点后两位。 let d1：Double = 20000000.0 let d2：Double = 1.2345我要查看：let s1 =字符串（格式：“ ????”，d1）// 20 000 000.00 let s2 = ...

Answer 1

let d1: Double = 20000000.0
let d2: Double = 1.2345

let formatter = NumberFormatter()
formatter.groupingSeparator = " "
formatter.numberStyle = .decimal
formatter.minimumFractionDigits = 2
formatter.maximumFractionDigits = 2
formatter.decimalSeparator = "." // Default separator is dependent to the current local.

print(formatter.string(for: d1)) // 20 000 000.00
print(formatter.string(for: d2)) // 1.23