所以我有一个对象数组,看起来像:
dataArray = [
{Revenue: 5, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 10, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 5, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 1, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"},
{Revenue: 4, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"}
]
我需要的是将其减少到另一个看起来像的对象数组:
reducedDataArray = [
{Revenue: 20, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 5, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"}
]
基本上,如果日期相同,则需要对收入进行求和,以便不存在同一日期的多个实例。不幸的是我只限于我们的Typescript版本,所以我没有所有很酷的ES6好东西来帮助解决这个问题。我尝试过使用像reduce()这样的东西,但我认为不知道我在做什么,这有点奇怪,这让我陷入迷茫。
任何建议或见解将不胜感激!
玩了一些循环,它的工作原理
dataArray = [
{Revenue: 5, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 10, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 5, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 1, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"},
{Revenue: 4, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"}
];
const getUnique=array=>{
return array.filter((value, index, self)=> {
return self.indexOf(value) === index;
});
}
let date=[];
let output=[];
for(const v of dataArray) date.push(v.Date);
for(const v of getUnique(date)){
let revenue=0,date=v,dateString;
for(const x of dataArray){
if(x.Date==v) revenue+=x.Revenue;
dateString=x.DateString;
}
output.push({
Revenue:revenue,
Date:v,
DateString:dateString
});
}
console.log(output);
您可以使用reduce
创建带有日期键的对象,然后将对象转换回数组。
let dataArray = [
{Revenue: 5, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 10, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 5, Date: "2018-06-05T00:00:00", DateString: "6/5/2018"},
{Revenue: 1, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"},
{Revenue: 4, Date: "2018-06-13T00:00:00", DateString: "6/13/2018"}
]
// We need to specify the type parameter explicitly, as it will not be inffered from initial value
let valuesObj = dataArray.reduce<{ [date: string]: typeof dataArray[number] }>((p, v) => {
const existing = p[v.Date];
if (existing) {
existing.Revenue += v.Revenue
} else {
p[v.Date] = Object.assign({}, v); //Create a copy so as to not change the original when we sum
}
return p;
}, {});
// You can use Object.values(valuesObj) if available
let values = Object.keys(valuesObj).map(k => valuesaObj[k]);
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