通过shell脚本从输出中提取id [duplicate]

Question

这个问题在这里已有答案：

• Parsing JSON with Unix tools 36回答

我在脚本shell中有一个变量，当我执行echo $ myvariable时。这是输出：

         {"networks":[{"status":"ACTIVE","router:external":true,"availability_zone_hints":[],"availability_zones":["nova"],
"ipv4_address_scope":null,"description":"",
"port_security_enabled":true,**"subnets":["56efe610-32af-4f03-a73d-14bcbf1c9ae1","18ca945c-8868-4549-b725-e11f04612663"],**
    "updated_at":"2018-02-26T04:55:25Z",
    *"tenant_id":"187d635aec4c43fe8e8918afb3a5c82e",*
    "created_at":"2018-02-26T04:55:12Z",
    "tags":[],"ipv6_address_scope":null,
    "mtu":1500,"is_default":true,"revision_number":7,
    "admin_state_up":true,"shared":false,
    "project_id":"187d635aec4c43fe8e8918afb3a5c82e",
    "id":"7697d4c6-5b4c-4ea9-a1d6-af7d7f716f2b","name":"public"

然后我试图提取子网id (56efe610-32af-4f03-a73d-14bcbf1c9ae1 and 18ca945c-8868-4549-b725-e11f04612663)和tenant_id（187d635aec4c43fe8e8918afb3a5c82e）。

我试过tenant_id这个shell脚本：

tenantid=$("$myvariable" | grep "tenant_id" | awk '{printf $2}')

echo $ tenantid我得到了相同的结果。

对于子网，我尝试了相同但我有相同的结果。

subnets=$(echo "$myvariable" | grep "subnets" | awk '{printf $1}')

先谢谢你们。

Answer 1

这似乎有效：

subnets=`echo $myvariable | egrep -o '"subnets":\[[-_A-Za-z0-9, "]*\]' | egrep -o '\[[-_A-Za-z0-9, "]*\]'`
tenant_id=`echo $myvariable | egrep -o '"tenant_id":"[-_A-Za-z0-9 ]*",'  | egrep -o ':"[-_A-Za-z0-9 ]*"' | egrep -o '"[-_A-Za-z0-9 ]*"'`

我不知道你想要的格式。