C#ListBox如何导出我从列表框中传递的名称的文件

问题描述 投票:0回答:1

**对不起,我的英语,但是我在Google翻译中不太了解,我会翻译。

我希望从列表框中选择要以与列表框中相同的名称导出的文件**

       private void downloadFile(object sender, EventArgs e)
    {
        string ip = txt_ip.Text;
        string user = txt_user.Text;
        string pass = txt_pass.Text;
        //string pathLocalFile = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.Desktop), "download_sftp_file.txt");
        try
        {
            SftpClient client = new SftpClient(ip, user, pass);
            client.Connect();

            string rmDer = dr_finder.Text;

            var files = client.ListDirectory(rmDer);


            if (rmDer == "")
            {
                client.Connect();

                string rmDerNow = "/";

                var filesName = client.ListDirectory(rmDerNow);

                foreach (var file in filesName)
                {
                    DirList.Items.Add(file.Name);
                    string result = Path.GetFileNameWithoutExtension(file.Name);
                    DirList.Items.Add(System.IO.Path.GetFileName(file.Name));
                }
                MessageBox.Show("List Directory Success!");
            }

            string pachRemFile = DirList.SelectedItem.ToString();
            string pachlocalFile = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.Desktop),"Server Ftp File.txt");

            Stream Filestream = File.OpenWrite(pachlocalFile);
            client.DownloadFile(pachRemFile,Filestream);
            client.Disconnect();
        }
        catch (Exception error)
        {
            MessageBox.Show(error.Message);
        }
    }
c# listbox
1个回答
0
投票

此对象是解决方案,我终于找不到任何人来帮助我。所以我帮了自己我以为他在这个网站上有好的程序员]

 SaveFileDialog savefile = new SaveFileDialog(); /* this here is my solution get a save as. */

            if (savefile.ShowDialog() == DialogResult.OK)   
            {
                string pachRemFile = DirList.SelectedItem.ToString();
                Stream Filestream = File.Open(savefile.FileName, FileMode.CreateNew);
                StreamWriter sw = new StreamWriter(Filestream);
                client.DownloadFile(pachRemFile, Filestream);
                client.Disconnect();
            }
    
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