删除重复的元素[重复的]

Question

此问题已经在这里有了答案：

Remove duplicate values from JS array [duplicate]（54个回答）

关闭4分钟前。

我在打字稿中有这个对象数组

[
  {target_col: "`qsze`", operation: "", isNew: false, operationNotCompiled: "", index: 25},
  {target_col: "`qsf`", operation: "", isNew: false, operationNotCompiled: "", index: 26},
  {target_col: "`amiu`", operation: "'jnhghghgh'", isNew: true, operationNotCompiled: "'jnhghghgh'",…},
  {target_col: "`amiu`", operation: "", isNew: false, operationNotCompiled: "", index: 27}
]

并且我想删除重复的元素。

我想如果没有重复的元素，则返回该对象。否则，如果元素重复，则删除具有operationNotCompiled=""的元素。

[如果有重复的元素并且2个元素具有operationNotCompiled=""，则删除一个。

2个元素重复===== >>> 2个元素具有相同的属性target_col。像这样2。

{target_col: "`amiu`", operation: "'jnhghghgh'", isNew: true, operationNotCompiled: "'jnhghghgh'",…},
{target_col: "`amiu`", operation: "", isNew: false, operationNotCompiled: "", index: 27}

Answer 1

const arr = [
  {target_col: "`qsze`", operation: "", isNew: false, operationNotCompiled: "", index: 25},
  {target_col: "`qsf`", operation: "", isNew: false, operationNotCompiled: "", index: 26},
  {target_col: "`amiu`", operation: "'jnhghghgh'", isNew: true, operationNotCompiled: "'jnhghghgh'"},
  {target_col: "`amiu`", operation: "", isNew: false, operationNotCompiled: "", index: 27}
]

function checkDuplicates(arr) {
  keys = []
  keysDuplicates = []
  arr.map(item => {
    if (keys.indexOf(item.target_col) == -1) {
      keys.push(item.target_col)
    } else {
      keysDuplicates.push(item.target_col)
    }
  })
  if (keysDuplicates.length) {
    return keysDuplicates.map(key => arr.filter(item => item.target_col === key))
  }
  
  return arr
}

console.log(checkDuplicates(arr));