无法读取带有[]和''的csv文件

Question

我正在尝试制作一个简单的程序，该程序生成一个URL列表，然后可以从中进行刮取。我怀疑我这样做是最有效的方法，但我有这个能力。

是否可以在列表中删除方括号和单引号？

#reads in list of towns that I want to scrape 
f = open('townList.csv', 'r')
reader = csv.reader(f)
towns= []

for row in reader:
    towns.append(row)

#base url. the rest of the url follows the convention 'town-state-abbreviation'
base_url = "https://datausa.io/profile/geo/"

url_list = []

for n in range(len(towns)):
    url = f'{base_url}{towns[n]}{"-pa"}'
    url_list.append(url)

print(url_list)

with open('urls.csv', 'w') as output:
    writer = csv.writer(output, lineterminator='\n')
    for val in url_list:
        writer.writerow([val]) 

我得到的是：

https://datausa.io/profile/geo/['Easton']-pa

我想得到：

https://datausa.io/profile/geo/Easton-pa

Answer 1

CVS阅读器是lists的迭代器。一个快速的解决方法可能是：

for row in reader:
    towns.append(row[0])

但是这暗示您的文件不是csv文件，而是一个简单的连续文件，每行有一个值。所以恕我直言，您想要的是：

#reads in list of towns that I want to scrape 
with open('townList.csv', 'r') as f:
    towns = [line.strip() for line in f]