我已经在这个工作了几天,我无法让它工作。我正在尝试读取文件并将一些信息累积到三个不同的字典中。这是归档在线课程的作业,并未发布解决方案。
这是要读取的文件:它从下面开始。
Restaurant name to rating:
# dict of {str: int}
{'Georgie Porgie': 87%,
'Queen St. Cafe': 82%,
'Dumplings R Us': 71%,
'Mexican Grill': 85%,
'Deep Fried Everything': 52%}
Price to list of restaurant names:
# dict of {str, list of str}
{'$': ['Queen St. Cafe', 'Dumplings R Us', 'Deep Fried Everything'],
'$$': ['Mexican Grill'],
'$$$': ['Georgie Porgie'],
'$$$$': []}
Cuisine to list of restaurant names:
# dict of {str, list of str}
{'Canadian': ['Georgie Porgie'],
'Pub Food': ['Georgie Porgie', 'Deep Fried Everything'],
'Malaysian': ['Queen St. Cafe'],
'Thai': ['Queen St. Cafe'],
'Chinese': ['Dumplings R Us'],
'Mexican': ['Mexican Grill'] (--->Ends here, this part is not included).
这是我正在使用的代码:
def read_restaurants(file):
""" (file) -> (dict, dict, dict)
Return a tuple of three dictionaries based on the information in the file:
- a dict of {restaurant name: rating%}
- a dict of {price: list of restaurant names}
- a dict of {cusine: list of restaurant names}
"""
# Initiate dictionaries
name_to_rating = {}
price_to_names = {'$': [], '$$': [], '$$$': [], '$$$$': []}
cuisine_to_names = {}
# Open the file
with open('restaurant_file_above.txt','r') as file:
# Build line list
lines = file.read().splitlines()
# Process the file
for i in range(0,len(lines),5):
# Read individual data
name = lines[i]
rating = int(lines[i+1].strip('%')) #error occurs here
price = lines[i+2]
cuisines = lines[i+3].split( ',' )
# Assign rating to name
name_to_rating[name]=rating;
# Assign names to price
price_to_names[price].append(name)
# Assign names to cuisine
for cuisine in cuisines:
cuisine_to_names.setdefault(cuisine,[]).append(name)
return name_to_rating, price_to_names, cuisine_to_names
我是初学者,所以非常感谢一些指导。我只是不知道还有什么可以尝试。顺便说一下,我正在使用Python 3.4.2。
您尝试读取的文件是最终输出,而不是原始输出。下面是docstring中原始数据的一个解决方案。
def read_restaurants(filename):
""" (file) -> (dict,dict,dict)
Return a tuple of three dictionaries based on the information in the file below
Georgie Porgie
87%
$$$
Canadian, Pub Food
Queen St. Cafe
82%
$
Malaysian, Thai
Dumplings R Us
71%
$
Chinese
Mexican Grill
85%
$$
Mexian
Deep Fried Everything
52%
$
Pub Food
- a dict of {restaurant name: rating}
- a dict of {price: list of restaurant names}
- a dict of {cusine: list of restaurant names}
"""
name_to_rating = {}
price_to_names = {'$':[],'$$':[],'$$$':[],'$$$$':[]}
cuisine_to_names = {}
#set incrementing number
i = 1
with open(filename,'rU') as f:
for line in f:
#check if blank line
if line.strip():
line = line.strip('\n')
#determine restaurant_name
if i == 1:
restaurant_name = line
#create dictionaries with restaurant_name
if i == 2:
rating = line
name_to_rating[restaurant_name] = rating
elif i == 3:
price = line
price_to_names[price].append(restaurant_name)
elif i == 4:
#could be multiple cuisines for each restaurant_name
cuisine_list = line.split(',')
for cuisine in cuisine_list:
cuisine_to_names[cuisine] = restaurant_name
#at blank line start increment over
else:
i = 0
i += 1
print name_to_rating
print price_to_names
print cuisine_to_names
return (name_to_rating,price_to_names,cuisine_to_names)
def main():
return read_restaurants('restaurants.txt')
if __name__ == "__main__":
main()
我认为上面的答案没有正确保存cuisine_by_names字典。见下面的代码。这有效:
def read_restuarants(file):
name_to_rating={}
price_to_names={'$':[],'$$':[],'$$$':[], '$$$$':[]}
cuisine_to_names={}
i=1
with open(file) as f:
contents = f.readlines()
for line in contents:
if line.strip():
l = line.strip()
if i ==1:
rest_name = l
if i ==2:
rating=l
name_to_rating[rest_name]=rating
if i==3:
price=l
price_to_names[l].append(rest_name)
if i==4:
cuisine_list = l.split(',')
for cuisine in cuisine_list:
if cuisine not in cuisine_to_names.keys():
cuisine_to_names[cuisine] = [rest_name]
else:
cuisine_to_names[cuisine].append(rest_name)
else:
i=0
i=i+1
print name_to_rating
print price_to_names
print cuisine_to_names