为什么我在“WHERE”附近的查询中出现语法错误? (多个表格)

问题描述 投票:-1回答:2

我还是新手,这是我第一次使用这些多表查询。为什么我会出现这样的错误?这是我的代码:

 String selectQuery =
            " select *" +
            "    from tableassign left outer join\n" +
            "         tableacc\n" +
            "         on tableassign.signeeid = tableacc.userid left outer join\n" +
            "         tableinfo\n" +
            "         on tableassign.signeeid = tableinfo.userid left outer join\n" +
                    " WHERE tableassign.signeedepid =?";
    Cursor data = db.rawQuery(selectQuery , new String[]{ signeedep });

错误:

android.database.sqlite.SQLiteException: near "WHERE": syntax error (code 1):
 , while compiling: select *  from tableassign left outer join  tableacc on
 tableassign.signeeid = tableacc.userid left outer join  tableinfo on 
tableassign.signeeid = tableinfo.userid left outer join WHERE 
tableassign.signeedepid =?
java jquery cursor left-join multiple-tables
2个回答
1
投票

看来你有一个复制/粘贴问题。删除left outer join之前的最后一个where

String selectQuery =
        " select *" +
        "    from tableassign left outer join\n" +
        "         tableacc\n" +
        "         on tableassign.signeeid = tableacc.userid left outer join\n" +
        "         tableinfo\n" +
        "         on tableassign.signeeid = tableinfo.userid\n" +
                " WHERE tableassign.signeedepid =?";
Cursor data = db.rawQuery(selectQuery , new String[]{ signeedep });

我的格式有点不同,主要是为了便于阅读:

String selectQuery =
        " SELECT *\n" +
        " FROM tableassign\n" +
        " LEFT JOIN tableacc ON tableassign.signeeid = tableacc.userid\n" +
        " LEFT JOIN tableinfo ON tableassign.signeeid = tableinfo.userid\n" +
        " WHERE tableassign.signeedepid =?";
Cursor data = db.rawQuery(selectQuery , new String[]{ signeedep });

1
投票

虽然我不确定您正在使用哪种结构化语言进行查询,但问题似乎在于您使用JOIN运算符。有关LEFT OUTER JOIN的Oracle文档显示了它的正确用法,其语法为:

TableExpression LEFT [ OUTER ] JOIN TableExpression
{
    ON booleanExpression |
    USING clause
}

最后的LEFT OUTER JOIN紧接在WHERE子句之前,而没有定义TableExpression。删除LEFT OUTER JOIN子句以删除错误。

 String selectQuery =
            " select *" +
            "    from tableassign left outer join\n" +
            "         tableacc\n" +
            "         on tableassign.signeeid = tableacc.userid left outer join\n" +
            "         tableinfo\n" +
            "         on tableassign.signeeid = tableinfo.userid" +
                    " WHERE tableassign.signeedepid =?";
    Cursor data = db.rawQuery(selectQuery , new String[]{ signeedep });
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