powershell xml到json空白文件

Question

我正在尝试使用powershell将xml文件转换为json。在那之前它非常简单，但源文件在我看来编码错误，当我应用convertto-json时，结构json为空：

XML中以r到：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<PnCG3_configuration>
  <domains>
    <domain Name="xxxxx">
      <players>
        <player targetId="00-1c-e6-02-0a-00" targetIdType="mac" label="test" middlewareFamily="gekkota-3" />
        <player />
      </players>
    </domain>
    <domain Name="xxxxxxx2">
      <players>
        <player targetId="00-1c-e6-02-0a-00" targetIdType="mac" label="OfficeChateaugiron-TV01" middlewareFamily="gekkota-3" />
        <player targetId="00-1c-e6-02-20-00" targetIdType="mac" label="test-01" middlewareFamily="gekkota-3" />
        <player targetId="00-1c-e6-02-0b-00" targetIdType="mac" label="test-test-TV01" middlewareFamily="gekkota-3" />
        <player targetId="00-1c-e6-02-20-00" targetIdType="mac" label="test-TV01-test" middlewareFamily="gekkota-3" />
        <player targetId="00-1c-e6-02-20-00" targetIdType="mac" label="test" middlewareFamily="gekkota-3" />
        <player targetId="00-1c-e6-02-09-00" targetIdType="mac" label="test-test-TV01" middlewareFamily="gekkota-3" />
        <player targetId="00-1c-e6-02-04-00" targetIdType="mac" label="test-test-TV01" middlewareFamily="gekkota-3" />
        <player />
      </players>
    </domain>

和Json Out：

[
    [

    ],
    [
        [
            [
                [
                    [

                    ],
                    [

                    ]
                ]
            ],
            [
                [
                    [

                    ],
                    [

                    ],
                    [

                    ],
                    [

                    ],
                    [

                    ],
                    [

                    ],

我的转换代码：

$xmlObject = [XML](Get-Content -Path $o)
$xmlObject | ConvertTo-JSON -depth 100 | Out-File "$o.json"

Answer 1

可悲的是，这并不容易。

看看我之前用过的这个GitHub Repo，完全按照你的要求去做。

您的代码将更改为：

Add-Type -Path .\Newtonsoft.Json.dll
$xmlObject = [XML](Get-Content -Path $o)
[Newtonsoft.Json.JsonConvert]::SerializeXmlNode($xmlObject ) | Out-File "$o.json"

Answer 2

使用这种方法确实为我创造了很多“空白”的噪音。

[Newtonsoft.Json.JsonConvert]::SerializeXmlNode($xmlObject) | Out-File "$o.json"

这种方式重新编译XML文件确实删除了空白并创建了一个整洁的对象。

[Newtonsoft.Json.JsonConvert]::SerializeXmlNode([xml] $xmlObject.OuterXML ) | Out-File "$o.json"