如何连接到需要身份验证的Java远程URL。我试图找到一种方法来修改以下代码，以便能够以编程方式提供用户名/密码，因此它不会抛出401。
URL url = new URL(String.format("http://%s/manager/list", _host + ":8080"));
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
您可以为http请求设置默认验证器，如下所示：
Authenticator.setDefault (new Authenticator() {
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication ("username", "password".toCharArray());
}
});
此外，如果您需要更多灵活性，可以查看Apache HttpClient，它将为您提供更多身份验证选项（以及会话支持等）
能够使用HttpsURLConnection设置auth
URL myUrl = new URL(httpsURL);
HttpsURLConnection conn = (HttpsURLConnection)myUrl.openConnection();
String userpass = username + ":" + password;
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userpass.getBytes()));
//httpsurlconnection
conn.setRequestProperty("Authorization", basicAuth);
这篇文章中提到的一些变化很少。和Base64来自java.util包。
ANDROID IMPLEMENTATION从Web服务请求数据/字符串响应的完整方法，请求使用用户名和密码进行授权
public static String getData(String uri, String userName, String userPassword) {
BufferedReader reader = null;
byte[] loginBytes = (userName + ":" + userPassword).getBytes();
StringBuilder loginBuilder = new StringBuilder()
.append("Basic ")
.append(Base64.encodeToString(loginBytes, Base64.DEFAULT));
try {
URL url = new URL(uri);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.addRequestProperty("Authorization", loginBuilder.toString());
StringBuilder sb = new StringBuilder();
reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line;
while ((line = reader.readLine())!= null){
sb.append(line);
sb.append("\n");
}
return sb.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if (null != reader){
try {
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
我这样做你需要这样做只需复制粘贴它很高兴
HttpURLConnection urlConnection;
String url;
// String data = json;
String result = null;
try {
String username ="[email protected]";
String password = "12345678";
String auth =new String(username + ":" + password);
byte[] data1 = auth.getBytes(UTF_8);
String base64 = Base64.encodeToString(data1, Base64.NO_WRAP);
//Connect
urlConnection = (HttpURLConnection) ((new URL(urlBasePath).openConnection()));
urlConnection.setDoOutput(true);
urlConnection.setRequestProperty("Content-Type", "application/json");
urlConnection.setRequestProperty("Authorization", "Basic "+base64);
urlConnection.setRequestProperty("Accept", "application/json");
urlConnection.setRequestMethod("POST");
urlConnection.setConnectTimeout(10000);
urlConnection.connect();
JSONObject obj = new JSONObject();
obj.put("MobileNumber", "+97333746934");
obj.put("EmailAddress", "[email protected]");
obj.put("FirstName", "Danish");
obj.put("LastName", "Hussain");
obj.put("Country", "BH");
obj.put("Language", "EN");
String data = obj.toString();
//Write
OutputStream outputStream = urlConnection.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));
writer.write(data);
writer.close();
outputStream.close();
int responseCode=urlConnection.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK) {
//Read
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(), "UTF-8"));
String line = null;
StringBuilder sb = new StringBuilder();
while ((line = bufferedReader.readLine()) != null) {
sb.append(line);
}
bufferedReader.close();
result = sb.toString();
}else {
// return new String("false : "+responseCode);
new String("false : "+responseCode);
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
这是一种原生的，不那么具有侵入性的选择，仅适用于您的通话。
URL url = new URL(“location address”);
URLConnection uc = url.openConnection();
String userpass = username + ":" + password;
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userpass.getBytes()));
uc.setRequestProperty ("Authorization", basicAuth);
InputStream in = uc.getInputStream();
您还可以使用以下内容，不需要使用外部包：
URL url = new URL(“location address”);
URLConnection uc = url.openConnection();
String userpass = username + ":" + password;
String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());
uc.setRequestProperty ("Authorization", basicAuth);
InputStream in = uc.getInputStream();
如果您在协议和域之间输入用户名和密码时使用正常登录，则这更简单。它也适用于登录和不登录。
示例网址：http://user:[email protected]/url
URL url = new URL("http://user:[email protected]/url");
URLConnection urlConnection = url.openConnection();
if (url.getUserInfo() != null) {
String basicAuth = "Basic " + new String(new Base64().encode(url.getUserInfo().getBytes()));
urlConnection.setRequestProperty("Authorization", basicAuth);
}
InputStream inputStream = urlConnection.getInputStream();
当我来到这里寻找Android-Java-Answer时，我将做一个简短的总结：
如果你想在Android中使用带有基本身份验证的java.net.URLConnection，请尝试以下代码：
URL url = new URL("http://www.mywebsite.com/resource");
URLConnection urlConnection = url.openConnection();
String header = "Basic " + new String(android.util.Base64.encode("user:pass".getBytes(), android.util.Base64.NO_WRAP));
urlConnection.addRequestProperty("Authorization", header);
// go on setting more request headers, reading the response, etc
请小心使用“Base64（）。encode（）”方法，我和我的团队遇到了400个Apache错误请求问题，因为它在生成的字符串末尾添加了\ r \ n。
由于Wireshark，我们发现它正在嗅探数据包。
这是我们的解决方案：
import org.apache.commons.codec.binary.Base64;
HttpGet getRequest = new HttpGet(endpoint);
getRequest.addHeader("Authorization", "Basic " + getBasicAuthenticationEncoding());
private String getBasicAuthenticationEncoding() {
String userPassword = username + ":" + password;
return new String(Base64.encodeBase64(userPassword.getBytes()));
}
希望能帮助到你！
使用此代码进行基本身份验证。
URL url = new URL(path);
String userPass = "username:password";
String basicAuth = "Basic " + Base64.encodeToString(userPass.getBytes(), Base64.DEFAULT);//or
//String basicAuth = "Basic " + new String(Base64.encode(userPass.getBytes(), Base64.No_WRAP));
HttpURLConnection urlConnection = (HttpURLConnection)url.openConnection();
urlConnection.setRequestProperty("Authorization", basicAuth);
urlConnection.connect();我想为您无法控制打开连接的代码提供答案。就像我在使用URLClassLoader从受密码保护的服务器加载jar文件时所做的那样。
Authenticator解决方案可以工作但缺点是它首先尝试在没有密码的情况下到达服务器，并且只有在服务器要求输入密码后才能提供密码。如果您已经知道服务器需要密码，这是不必要的往返。
public class MyStreamHandlerFactory implements URLStreamHandlerFactory {
private final ServerInfo serverInfo;
public MyStreamHandlerFactory(ServerInfo serverInfo) {
this.serverInfo = serverInfo;
}
@Override
public URLStreamHandler createURLStreamHandler(String protocol) {
switch (protocol) {
case "my":
return new MyStreamHandler(serverInfo);
default:
return null;
}
}
}
public class MyStreamHandler extends URLStreamHandler {
private final String encodedCredentials;
public MyStreamHandler(ServerInfo serverInfo) {
String strCredentials = serverInfo.getUsername() + ":" + serverInfo.getPassword();
this.encodedCredentials = Base64.getEncoder().encodeToString(strCredentials.getBytes());
}
@Override
protected URLConnection openConnection(URL url) throws IOException {
String authority = url.getAuthority();
String protocol = "http";
URL directUrl = new URL(protocol, url.getHost(), url.getPort(), url.getFile());
HttpURLConnection connection = (HttpURLConnection) directUrl.openConnection();
connection.setRequestProperty("Authorization", "Basic " + encodedCredentials);
return connection;
}
}
这将注册一个新的协议my，当添加凭据时，该协议将被http取代。因此，当创建新的URLClassLoader时，用http替换my，一切都很好。我知道URLClassLoader提供了一个带有URLStreamHandlerFactory的构造函数，但如果URL指向jar文件，则不使用此工厂。
从Java 9开始，您就可以做到这一点
URL url = new URL("http://www.example.com");
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
connection.setAuthenticator(new Authenticator() {
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication ("USER", "PASS".toCharArray());
}
});