为什么我的程序在打开网络设备时遇到问题

Question

我看了libtins，并在示例中找到了[[ARP Monitor示例] >>。示例代码在这里：

#include <tins/tins.h>
#include <map>
#include <iostream>
#include <functional>

using std::cout;
using std::endl;
using std::map;
using std::bind;

using namespace Tins;

class arp_monitor {
public:
    void run(Sniffer& sniffer);
private:
    bool callback(const PDU& pdu);

    map<IPv4Address, HWAddress<6>> addresses;
};

void arp_monitor::run(Sniffer& sniffer) {
    sniffer.sniff_loop(
        bind(
            &arp_monitor::callback,
            this,
            std::placeholders::_1
        )
    );
}

bool arp_monitor::callback(const PDU& pdu) {
    // Retrieve the ARP layer
    const ARP& arp = pdu.rfind_pdu<ARP>();
    // Is it an ARP reply?
    if (arp.opcode() == ARP::REPLY) {
        // Let's check if there's already an entry for this address
        auto iter = addresses.find(arp.sender_ip_addr());
        if (iter == addresses.end()) {
            // We haven't seen this address. Save it.
            addresses.insert({ arp.sender_ip_addr(), arp.sender_hw_addr()});
            cout << "[INFO] " << arp.sender_ip_addr() << " is at "
                 << arp.sender_hw_addr() << std::endl;
        }
        else {
            // We've seen this address. If it's not the same HW address, inform it
            if (arp.sender_hw_addr() != iter->second) {
                cout << "[WARNING] " << arp.sender_ip_addr() << " is at " 
                     << iter->second << " but also at " << arp.sender_hw_addr() 
                     << endl;
            }
        }
    }
    return true;
}

int main(int argc, char* argv[]) {
    if(argc != 2) {
        cout << "Usage: " <<* argv << " <interface>" << endl;
        return 1;
    }
    arp_monitor monitor;
    // Sniffer configuration
    SnifferConfiguration config;
    config.set_promisc_mode(true);
    config.set_filter("arp");

    try {
        // Sniff on the provided interface in promiscuous mode
        Sniffer sniffer(argv[1], config);

        // Only capture arp packets
        monitor.run(sniffer);
    }
    catch (std::exception& ex) {
        std::cerr << "Error: " << ex.what() << std::endl;
    }
}

我在这里运行此代码：

myprogram.exe eth0

结果是：

错误：打开适配器时出错：系统找不到给定的设备。 （20）

[以上词语的定义：

eth0：我的网络设备

libtins：高级，多平台C ++网络数据包嗅探和制作库

ARP：地址解析协议

我在Windows上仅对一个名为“ Shadow”的用户运行过它>

Image of the Users Directory

我查看了libtins，并在示例中找到了ARP Monitor示例。示例代码在这里是这样的：#include

#include #include

Answer 1

基于te OP上传的图像，我只能得出结论，我认为他在Windows上运行该程序是正确的，所以我只从libtins's documentation复制：

为了在Windows上捕获数据包，您可以首先列出所有网络接口。您可以使用NetworkInterface类轻松地做到这一点：