使用sed为korn shell中的变量内容添加前缀

Question

我试图远离所有运行时临时文件。我能够用运行时变量替换所有这些变量，但是当我使用带变量的命令时，一个命令让我很难。

rimco内容：包含文件位置

   /home/bim 
   /home/ram 
   /home/gps 
   /home/hdr 
   /home/pal 

bim内容：包含一组数字

28800,1536,14400,768
11100,12312,902,321
3044,1536,1290,334
3044,1536,1290,334
11100,12312,902,321
28800,1536,14400,768

目标是在找到我正在寻找的数字时为变量$output添加前缀。该行存储在$output中，前缀为$dte

dte="available" 
for f in $(cat rimco)
  do 
   out=`grep 768 $f`
     output+=`echo -e "\n$out"| sed "s/^/$dte,/"`
 done

好吧，结果是没有吸引力，dte内容，到处都是

available,
available,28800,1536,14400,768
available,28800,1536,14400,768available,
available,28800,1536,14400,768
available,28800,1536,14400,768available,
available,28800,1536,14400,768
available,28800,1536,14400,768available,
available,28800,1536,14400,768
available,28800,1536,14400,768available,
available,28800,1536,14400,768
available,28800,1536,14400,768

目标是得到这个

available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768

知道怎么解决这个问题吗？

谢谢

Answer 1

这是我对许多文件的回答。使用额外的变量结果连接和grep来摆脱空行：

dte="available"
result="" 
for f in $(cat rimco)
  do 
     out=`grep 768 $f`
     output=`echo -e "$out" | sed "s/^/$dte,/"`
     result="$result\n$output"
 done

echo -e "$result" | grep -v "^$"

返回：

available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768
available,28800,1536,14400,768

Answer 2

如果你将grep更改为一个衬里它可以工作（删除for循环）：

dte="available"
files=$(cat rimco)
out=`grep 768 $files`
output=`echo -e "$out" | sed "s/^.*:/$dte,/"`
echo -e "$output"

sed现在用$ dte字符串替换文件名（grep的结果）加冒号：