Laravel Passport尝试获取非对象的属性“秘密”

Question

我正在使用laravel并尝试使用Authenthication制作一个Laravel passport。因此，我通过查看文档和youtube完成了此操作，但出现此错误。这是我要求的AuthController和错误。

AuthController.php

public function register(Request $request) 
    {
        $validatedData = $request->validate([
            'name'=>'required|max:55',
            'email'=>'email|required|unique:users',
            'password'=>'required|confirmed',
            'who'=>'required'
        ]);

        $validatedData['password'] = bcrypt($request->password);

        $user = User::create($validatedData);

        // Get access token
        $accessToken = $user->createToken('authToken')->accessToken;

        return response(['user' => $user, 'access_token' => $accessToken]);
    }

ErrorsException

{
    "message": "Trying to get property 'secret' of non-object",
    "exception": "ErrorException",
    "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\passport\\src\\PersonalAccessTokenFactory.php",
    "line": 96,
    "trace": [
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\passport\\src\\PersonalAccessTokenFactory.php",
            "line": 96,
            "function": "handleError",
            "class": "Illuminate\\Foundation\\Bootstrap\\HandleExceptions",
            "type": "->"
        },
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\passport\\src\\PersonalAccessTokenFactory.php",
            "line": 71,
            "function": "createRequest",
            "class": "Laravel\\Passport\\PersonalAccessTokenFactory",
            "type": "->"
        },
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\passport\\src\\HasApiTokens.php",
            "line": 67,
            "function": "make",
            "class": "Laravel\\Passport\\PersonalAccessTokenFactory",
            "type": "->"
        },
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\app\\Http\\Controllers\\Api\\AuthController.php",
            "line": 26,
            "function": "createToken",
            "class": "App\\User",
            "type": "->"
        },
        {
            "function": "register",
            "class": "App\\Http\\Controllers\\Api\\AuthController",
            "type": "->"
        },
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\framework\\src\\Illuminate\\Routing\\Controller.php",
            "line": 54,
            "function": "call_user_func_array"
        },
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\framework\\src\\Illuminate\\Routing\\ControllerDispatcher.php",
            "line": 45,
            "function": "callAction",
            "class": "Illuminate\\Routing\\Controller",
            "type": "->"
        },
        {
            "file": "C:\\Panji\\xampp\\htdocs\\papa\\vendor\\laravel\\framework\\src\\Illuminate\\Routing\\Route.php",
            "line": 225,
            "function": "dispatch",
            "class": "Illuminate\\Routing\\ControllerDispatcher",
            "type": "->"
        },
.
.
.
}

我已经在Google上进行搜索，但是找不到任何提及Trying to get property 'secret' of non-object的内容。我已经尝试过php artisan passport:install，所以我得到了personal_access_clients，但没有任何效果。

NB

它实际上已经注册了用户，但是收到了此错误响应。

Answer 1

Passport中唯一使用该名称的属性的代码是映射到Laravel\Passport\Client DB表的模型oauth_clients，因此，我建议检查该表是否已创建并可供您的应用访问。