在邮件合并Google表格中创建超链接

Question

我在 Google 表格中创建了独特的预填写 Google 表单链接，并希望使用邮件合并为每个参与者发送此独特的链接。

该链接有效感谢帮助。但我想在模板的文本中嵌入超链接，而不是直接发送链接。有什么建议吗？仍在尝试使用其他人的模板来学习应用程序脚本，因此我们将不胜感激。非常感谢！

电流输出

预期输出

const RECIPIENT_COL  = "Email";
const EMAIL_SENT_COL = "Email Sent";
 
function onOpen() {
  const ui = SpreadsheetApp.getUi();
  ui.createMenu('Mail Merge')
      .addItem('Send Emails', 'sendEmails')
      .addToUi();
}
 
function sendEmails(subjectLine, sheet=SpreadsheetApp.getActiveSheet()) {
   if (!subjectLine){
    subjectLine = Browser.inputBox("Mail Merge", 
                                      "Type or copy/paste the subject line of the Gmail " +
                                      "  ",
                                      Browser.Buttons.OK_CANCEL);
                                      
    if (subjectLine === "cancel" || subjectLine == ""){ 
    // if no subject line finish up
    return;
    }
  }
  
  // get the draft Gmail message to use as a template
  const emailTemplate = getGmailTemplateFromDrafts_(subjectLine);
  
  // get the data from the passed sheet
  const dataRange = sheet.getDataRange();
  const data = dataRange.getDisplayValues();

  // assuming row 1 contains our column headings
  const heads = data.shift(); 
  
  const emailSentColIdx = heads.indexOf(EMAIL_SENT_COL);
  
  const obj = data.map(r => (heads.reduce((o, k, i) => (o[k] = r[i] || '', o), {})));

  // used to record sent emails
  const out = [];

  // loop through all the rows of data
  obj.forEach(function(row, rowIdx){
    // only send emails is email_sent cell is blank and not hidden by filter
    if (row[EMAIL_SENT_COL] == ''){
      try {
        const msgObj = fillInTemplateFromObject_(emailTemplate.message, row);

        GmailApp.sendEmail(row[RECIPIENT_COL], msgObj.subject, msgObj.text, {
          htmlBody: msgObj.html,
          //bcc: '[email protected]',
          //cc: '[email protected]',
          //from: '[email protected]',
          // name: '[email protected]',
          // replyTo: '[email protected]',
          // noReply: true, // if the email should be sent from a generic no-reply email address (not available to gmail.com users)
          attachments: emailTemplate.attachments
        });
        // modify cell to record email sent date
        out.push([new Date()]);
      } catch(e) {
        // modify cell to record error
        out.push([e.message]);
      }
    } else {
      out.push([row[EMAIL_SENT_COL]]);
    }
  });
  
  // updating the sheet with new data
  sheet.getRange(2, emailSentColIdx+1, out.length).setValues(out);
  
  function getGmailTemplateFromDrafts_(subject_line){
    try {
      const drafts = GmailApp.getDrafts();
      const draft = drafts.filter(subjectFilter_(subject_line))[0];
      const msg = draft.getMessage();
      const attachments = msg.getAttachments();
      return {message: {subject: subject_line, text: msg.getPlainBody(), html:msg.getBody()}, 
              attachments: attachments};
    } catch(e) {
      throw new Error("Oops - can't find Gmail draft");
    }

    function subjectFilter_(subject_line){
      return function(element) {
        if (element.getMessage().getSubject() === subject_line) {
          return element;
        }
      }
    }
  }
  
  function fillInTemplateFromObject_(template, data) {
    let template_string = JSON.stringify(template);
     data['Google Form Link'] = encodeURI(data['Google Form Link']);

    // token replacement
    template_string = template_string.replace(/{{[^{}]+}}/g, key => {
      return data[key.replace(/[{}]+/g, "")] || "";
    });
    return  JSON.parse(template_string);
  }
}

Answer 1

您需要将链接包含在

href

标签内才能创建超链接。

代码：

data['Google Form Link'] = "<a href='" + encodeURI(data['Google Form Link']) + "'>Click Here</a>";

输出：

Answer 2

这样做：

var value = '=HYPERLINK("www.yourLink.com", "Click Here")';

Answer 3

您介意与我分享上述问题吗？我还在纠结如何解决这个问题。

谢谢你