需要清洁我的代码以使其干燥的建议

Question

我正在做一个练习，在那里我需要创建一个代码，我将速度限制设置为70m / h。对于每5英里的增量，代码将增加1分，在5分之后，许可证将被吊销。

我制作代码的方式有效，但是过于重复，我想不出一种方法，可以使循环变得更简单，而不必重复很多次。

有什么建议吗？

def speed_check(speed):
    speed_limit = 70
    points = 0

    if speed <= speed_limit:
        return "Speed is OK"
    elif (speed < speed_limit + 5) and (speed > speed_limit):
        points += 1
        return "Points taken {}!".format(points)
    elif (speed < speed_limit + 10) and (speed > speed_limit):
        points += 2
        return "Points taken {}!".format(points)
    elif (speed < speed_limit + 15) and (speed > speed_limit):
        points += 3
        return "Points taken {}!".format(points)
    elif (speed < speed_limit + 20) and (speed > speed_limit):
        points += 4
        return "Points taken {}!".format(points)
    else:
        points += 5
        return "Points taken {}!\nYour license has been revoked".format(points)


your_speed = int(input("Enter speed: "))
print(speed_check(your_speed))

Answer 1

import math

def speed_check(speed):
    speed_limit = 70
    points = 0

    if speed > speed_limit:
      amountOverSpeedLimit = (speed - speed_limit)
      points = math.floor(amountOverSpeedLimit/5)

    return "Points taken {}!".format(points)

your_speed = int(input("Enter speed: "))
print(speed_check(your_speed))

您可以使用math.floor和一些除法来获得相同的结果。当您超过4点或速度未超出限制时，这并不能解决该消息，但您应该可以将其添加。