无法计算如何从MySql查询中获取数据

问题描述 投票:0回答:1

我早些时候问过一个有关如何执行此查询的问题,并收到了好评。不幸的是,它比我通常运行的查询要先进一些,因此我无法弄清楚如何检索结果并将其显示在我的网页上。这是原始问题的链接original question

     <!-- Data list table --> 
    <table class="table table-bordered">
        <thead class="thead-dark">
            <tr>
                <th>Name</th>
                <th>Jan</th>
                <th>Feb</th>
                <th>Mar</th>
                <th>Apr</th>
                <th>May</th>
                <th>Jun</th>
                <th>Jul</th>
                <th>Aug</th>
                <th>Sep</th>
                <th>Oct</th>
                <th>Nov</th>
                <th>Dec</th>
                <th>AVG</th>
            </tr>
        </thead>
        <tbody>
    <?php

    $result = $db->query("SELECT name,
       COALESCE(AVG(CASE WHEN mth = 1 THEN PTS END), 0) AS Jan,
       COALESCE(AVG(CASE WHEN mth = 2 THEN PTS END), 0) AS Feb,
       COALESCE(AVG(CASE WHEN mth = 3 THEN PTS END), 0) AS Mar,
       COALESCE(AVG(CASE WHEN mth = 4 THEN PTS END), 0) AS Apr,
       -- repeat for May to November
       COALESCE(AVG(CASE WHEN mth = 12 THEN PTS END), 0) AS `Dec`,
       AVG(PTS) AS AVG
   FROM (
   SELECT Name, PTS AS PTS, MONTH(STR_TO_DATE(DATE, '%a %b %e %H:%i:%s %Y')) AS mth
   FROM data
    ) d
    GROUP BY name");


    while($row = mysqli_fetch_array($result)) {

            ?>

         <tr>
                <td><?php echo $row[Name]; ?></td>
                <td class = "gScore-<?php echo $row[Jan]; ?>"></td>
                <td class = "gScore-<?php echo $ptsFeb; ?>"></td>
                <td class = "gScore-<?php echo $ptsMar; ?>"></td>
                <td class = "gScore-<?php echo $ptsApr; ?>"></td>
                <td class = "gScore-<?php echo $ptsMay; ?>"></td>
                <td class = "gScore-<?php echo $ptsJun; ?>"></td>
                <td class = "gScore-<?php echo $ptsJul; ?>"></td>
                <td class = "gScore-<?php echo $ptsAug; ?>"></td>
                <td class = "gScore-<?php echo $ptsSep; ?>"></td>
                <td class = "gScore-<?php echo $ptsOct; ?>"></td>
                <td class = "gScore-<?php echo $ptsNov; ?>"></td>
                <td class = "gScore-<?php echo $ptsDec; ?>"></td>
                <td><?php echo $avgGrade; ?></td>
            </tr>
        <?php   


}
php html mysql
1个回答
0
投票

您有几个问题:

  1. $row的索引需要用引号引起来,例如$row['name']否则,您将收到很多“未定义的常量”警告;
  2. $row['Jan']是检索月度数据的正确方法,您需要复制其他每个月的数据;
  3. $avgGrade替换$row['AVG']
  4. 我不确定您要使用的是什么
<td class = "gScore-<?php echo $row[Jan]; ?>"></td>

您实际上要不要

<td class = "gScore"><?php echo $row[Jan]; ?></td>
  1. 您需要将-- repeat for May to November行添加到查询中,即
    $result = $db->query("SELECT name,
       COALESCE(AVG(CASE WHEN mth = 1 THEN PTS END), 0) AS Jan,
       COALESCE(AVG(CASE WHEN mth = 2 THEN PTS END), 0) AS Feb,
       COALESCE(AVG(CASE WHEN mth = 3 THEN PTS END), 0) AS Mar,
       COALESCE(AVG(CASE WHEN mth = 4 THEN PTS END), 0) AS Apr,
       COALESCE(AVG(CASE WHEN mth = 5 THEN PTS END), 0) AS May,
       COALESCE(AVG(CASE WHEN mth = 6 THEN PTS END), 0) AS Jun,
       COALESCE(AVG(CASE WHEN mth = 7 THEN PTS END), 0) AS Jul,
       COALESCE(AVG(CASE WHEN mth = 8 THEN PTS END), 0) AS Aug,
       COALESCE(AVG(CASE WHEN mth = 9 THEN PTS END), 0) AS Sep,
       COALESCE(AVG(CASE WHEN mth = 10 THEN PTS END), 0) AS Oct,
       COALESCE(AVG(CASE WHEN mth = 11 THEN PTS END), 0) AS Nov,
       COALESCE(AVG(CASE WHEN mth = 12 THEN PTS END), 0) AS `Dec`,
       AVG(PTS) AS AVG
   FROM (
   SELECT name, PTS AS PTS, MONTH(STR_TO_DATE(DATE, '%a %b %e %H:%i:%s %Y')) AS mth
   FROM data
    ) d
    GROUP BY name");
© www.soinside.com 2019 - 2024. All rights reserved.