从python中的嵌套字典中删除NaN值。我的嵌套字典如下所示:
my_dict = {'abc':{'a':0.987, 'b':0.765, 'c': numpy.nan}, 'mda':{'a':0.145, 'b':0.584, 'e':numpy.nan}, 'fop':{'a':0.145, 'b': numpy.nan, 'c':0.485}}
我想从嵌套字典中删除Nan值,预期结果如下:
my_dict = {'abc':{'a':0.987, 'b':0.765}, 'mda':{'a':0.145, 'b':0.584}, 'fop':{'a':0.145, 'c':0.485}}
我写下面的代码从嵌套字典中删除Nan的:
def remove_nan_from_dict(my_dict):
new_dict = {}
original_dict = collections.defaultdict()
from math import isnan
for k, v in my_dict.items():
for k1, v1 in v.items():
print(v1)
if not isnan(v1):
new_dict[k1] = v1
print(new_dict)
original_dict[k] = new_dict
# print(original_dict.items())
return original_dict
但要低于字典:
defaultdict(None, {'abc': {'a': 0.145, 'b': 0.584, 'c': 0.485}, 'mda': {'a': 0.145, 'b': 0.584, 'c': 0.485}, 'fop': {'a': 0.145, 'b': 0.584, 'c': 0.485}})
你可以在这里使用dict理解并检查值是否为np.nan
:
new_dict = {k: {a: b for a, b in v.items() if not np.isnan(b)} for k, v in my_dict.items()}
你可以使用这样的2个简单循环:
my_dict = {'abc':{'a':0.987, 'b':0.765, 'c': numpy.nan}, 'mda':{'a':0.145, 'b':0.584, 'e':numpy.nan}, 'fop':{'a':0.145, 'b': numpy.nan, 'c':0.485}}
for items in my_dict:
get_key = my_dict[items]
for key, values in get_key.copy().items():
if numpy.isnan(values):
del get_key[key]
my_dict
> {'abc': {'a': 0.987, 'b': 0.765},
'mda': {'a': 0.145, 'b': 0.584},
'fop': {'a': 0.145, 'c': 0.485}}