从 Blazor WebAssembly 将视频文件上传到 api.video

Question

尝试将视频上传到 api.video 时遇到困难

我使用的是 Blazor、.Net core 8。

这是他们的文档：https://docs.api.video/reference/api/Videos，特别是“上传视频”部分。

我可以做其他所有事情，AccessToken、删除视频、创建视频等...

这就是我所拥有的：

public async Task OnSelectFile (InputFileChangeEventArgs e)
{
    if (e.File != null)
    {
        long maxFileSize = 1024L * 1024L * 1024L * 2L;

        string contentType = "";
        string sourceB64 = "";
        
        IBrowserFile videoFile = e.File;
        string file;
        var buffers = new byte[videoFile.Size];
        await videoFile.OpenReadStream(maxFileSize).ReadAsync(buffers);
        file = Convert.ToBase64String(buffers);

        if (await videoClient.UploadVideo(currentVideoObject, file))
        {
            toast.ShowToast("Successfully uploaded Video", ToastLevel.Success);
        }
        else
        {
            toast.ShowToast("Failed to upload video", ToastLevel.Error);
        }
    }
}

public async Task<bool> UploadVideo (VideoObject video, string file)
{
    try
    {
        var request = new HttpRequestMessage(new HttpMethod("Post"), "https://ws.api.video/videos/"+video.Id+"/source");
        request.Headers.TryAddWithoutValidation("accept", "application/json");
        request.Headers.Authorization = new AuthenticationHeaderValue("Bearer", token.accesstoken);
        request.Content = new StringContent("{\"bytes\":\""+file+"\"}");

        var response = await client.SendAsync(request);

        if (response.IsSuccessStatusCode)
        { 
            return true;
        }
    }
    catch (Exception ex)
    {
        Console.WriteLine("Failed to upload video" + ex);
    }

    return false ;
}

我得到的回复是：

错误的请求，请求中不存在该文件。

Answer 1

您无法将文件作为字符串传递，因为 api.video API 仅接受多部分形式。您必须确保通过从磁盘读取文件来传递文件流。您可以通过将代码更改为如下所示来做到这一点：

var client = new HttpClient();
var request = new HttpRequestMessage(HttpMethod.Post, "https://ws.api.video/videos/:videoId/source");
request.Headers.Add("Content-Range", "");
request.Headers.Add("Accept", "application/json");
request.Headers.Add("Authorization", "Basic base_64_api_key");
var content = new MultipartFormDataContent();
content.Add(new StreamContent(File.OpenRead("/path/to/file.mp4")), "file", "/path/to/file.mp4");
request.Content = content;
var response = await client.SendAsync(request);
response.EnsureSuccessStatusCode();
Console.WriteLine(await response.Content.ReadAsStringAsync());