在我的程序中,我有一类具有4个参数的播放器。在Post方法中,如果我缺少参数,请尝试抛出handleMissingParameter。但是在PostMan中,当我像这样键入json时:{“昵称”:“某物”,“ fisrtname”:“”,“ lastname”:“某物”,“电子邮件”:“”
}
没有错误,一切顺利,并向我展示了创造!信息。请问我在哪里弄错了,可以帮我!
///////////////////////////////////////////////// /这是我的张贴方法:
@PostMapping
public ResponseEntity<?> createPlayer(@RequestBody Player player) throws MissingServletRequestParameterException {
Player findplayer = repo.findByNickname(player.getNickname());
if(findplayer != null) {
return ResponseEntity.status(409).body("Conflict!");
}
repo.save(player);
return ResponseEntity.status(201).body("Created!");
}
////////////////////////////////////
这里是我的handleException与我的Post方法在同一位置:
@ExceptionHandler(MissingServletRequestParameterException.class)
public void handleMissingParams(MissingServletRequestParameterException ex) {
String name = ex.getParameterName();
System.out.println(name + " parameter is missing");
}
///////////////////////////////////////////////// ////
这是我的播放器类:
package thesisMongoProject;
import org.springframework.data.annotation.Id;
import org.springframework.data.mongodb.core.mapping.Document;
@Document(collection = "player")
public class Player {
@Id
private String nickname;
private String firstname;
private String lastname;
private String email;
public Player(String nickname, String firstname, String lastname, String email) {
super();
this.nickname = nickname;
this.firstname = firstname;
this.lastname = lastname;
this.email = email;
}
public String getNickname() {
return nickname;
}
public void setNickname(String nickname) {
this.nickname = nickname;
}
public String getFirstname() {
return firstname;
}
public void setFirstname(String firstname) {
this.firstname = firstname;
}
public String getLastname() {
return lastname;
}
public void setLastname(String lastname) {
this.lastname = lastname;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
@Override
public String toString() {
return "Player [nickname=" + nickname + ", firstname=" + firstname + ", lastname=" + lastname + ", email="
+ email + "]";
}
}
////////////////////////////
不要使用MissingServletRequestParameterException但要使用Bean Vaidation。
首先将@Valid注释添加到Player参数:
@PostMapping
public ResponseEntity<?> createPlayer(@RequestBody @Valid Player player) {
Player findplayer = repo.findByNickname(player.getNickname());
if(findplayer != null) {
return ResponseEntity.status(409).body("Conflict!");
}
repo.save(player);
return ResponseEntity.status(201).body("Created!");
}
然后将验证添加到播放器:
@Document(collection = "player")
public class Player {
@Id
@NotBlank
private String nickname;
@NotBlank
private String firstname;
@NotBlank
private String lastname;
@NotBlank
private String email;