在OSMnx地图顶部绘制折线

Question

[使用OSMnx库，我正在尝试在底图的顶部绘制多边形的线（每个定义的坐标不遵守底层网络），但是没有运气。我确定我拥有的坐标在边界之内，并且添加它们时也不会出错。

这是我当前的代码，该代码生成基本地图，并在网络下方添加一个多面图层。因此可以添加多边形，这使我认为坐标可能存在投影问题，但是我并没有运气设置不同的投影。

任何帮助将不胜感激！

import matplotlib.pyplot as plt
from descartes import PolygonPatch
from shapely.geometry import Polygon, MultiPolygon
import osmnx as ox
ox.config(log_console=True, use_cache=True)
ox.__version__

def plot(geometries):
  # get the place shape
  gdf = ox.gdf_from_place('Copenhagen Municipality,Denmark')
  gdf = ox.project_gdf(gdf)

  # get the street network, with retain_all=True to retain all the disconnected islands' networks
  G = ox.graph_from_place('Copenhagen Municipality,Denmark', network_type='drive', retain_all=True)
  G = ox.project_graph(G)  

  fig, ax = ox.plot_graph(G, fig_height=10, show=False, close=False, edge_color='#777777')

  # Add shape from gdf
  for geometry in gdf['geometry'].tolist():
    if isinstance(geometry, (Polygon, MultiPolygon)):
      if isinstance(geometry, Polygon):
        geometry = MultiPolygon([geometry])
      for polygon in geometry:
        patch = PolygonPatch(polygon, fc='#cccccc', ec='k', linewidth=3, alpha=0.1, zorder=-1)
        ax.add_patch(patch)  

  # Add lines:
  for geometry in geometries:
    if isinstance(geometry, (Polygon, MultiPolygon)):
      if isinstance(geometry, Polygon):
        geometry = MultiPolygon([geometry])
        for polygon in geometry:
          patch = PolygonPatch(polygon, fc='#148024', ec='#777777', linewidth=10, alpha=1, zorder=2)
          ax.add_patch(patch)

  plt.savefig('images/cph.png', alpha=True, dpi=300)

plot(geometries)

geometries是一个包含如下多边形的列表：

POLYGON ((55.6938796 12.5584122, 55.6929711 12.5585957, 55.6921317 12.5579927, 55.6916918 12.5564539, 55.6909246 12.5553629, 55.6901215 12.554119, 55.6891181 12.5531433, 55.6881469 12.5526575, 55.687502 12.5538862, 55.6866445 12.5530816, 55.6856769 12.5524416, 55.6848185 12.5515929, 55.6838506 12.551074, 55.6829915 12.5504047, 55.6821492 12.5498124, 55.6812104 12.5492503, 55.680311 12.5486803, 55.6792187 12.547724, 55.6783172 12.5472156, 55.6774282 12.5466767, 55.6765291 12.5461124, 55.6755652 12.5453961, 55.6747743 12.5445313, 55.6738159 12.5439029, 55.673417 12.5454132, 55.6733398 12.5470051, 55.6731045 12.5486561, 55.6726013 12.5501493, 55.6727833 12.5520672, 55.6716717 12.5525378, 55.6706619 12.5528382, 55.6698239 12.5521737))
POLYGON ((55.6693768 12.5509383, 55.6684025 12.5511539, 55.6677405 12.5500371, 55.6668188 12.5501435, 55.6658323 12.550075, 55.665264 12.5487917, 55.6649187 12.5473085, 55.6645313 12.5457653))

Answer 1

在geopandas数据框中，地理坐标为（经度，纬度）。这是一个简单的演示代码，可以绘制一些示例数据。

import geopandas as gpd
import pandas as pd
import matplotlib.pyplot as plt
import osmnx as ox
from shapely import wkt  #need wkt.loads

# simple plot of OSM data
gdf = ox.gdf_from_place('Copenhagen Municipality,Denmark')
gdf = gpd.GeoDataFrame(gdf, crs={'init': 'epsg:4326'})  #set CRS
ax1 = gdf.plot(color='lightgray')  # grab axis as `ax1` for reuse

# prep the polygons to plot on the axis `ax1`
# use (longitude latitude), and the last point must equal the 1st
pgon1 = "POLYGON((12.5584122 55.6938796, 12.5585957 55.6929711, 12.5579927 55.6921317, 12.5564539 55.6916918, 12.5553629 55.6909246, 12.554119 55.6901215, 12.5531433 55.6891181, 12.5526575 55.6881469, 12.5538862 55.687502, 12.5530816 55.6866445, 12.5524416 55.6856769, 12.5515929 55.6848185, 12.551074 55.6838506, 12.5504047 55.6829915, 12.5498124 55.6821492, 12.5492503 55.6812104, 12.5486803 55.680311, 12.547724 55.6792187, 12.5472156 55.6783172, 12.5466767 55.6774282, 12.5461124 55.6765291, 12.5453961 55.6755652, 12.5445313 55.6747743, 12.5439029 55.6738159, 12.5454132 55.673417, 12.5470051 55.6733398, 12.5486561 55.6731045, 12.5501493 55.6726013, 12.5520672 55.6727833, 12.5525378 55.6716717, 12.5528382 55.6706619, 12.5521737 55.6698239, 12.5584122 55.6938796))"
pgon2 = "POLYGON((12.5509383 55.6693768, 12.5511539 55.6684025, 12.5500371 55.6677405, 12.5501435 55.6668188, 12.550075 55.6658323, 12.5487917 55.665264, 12.5473085 55.6649187, 12.5457653 55.6645313, 12.5509383 55.6693768))"

# create dataframe of the 2 polygons
d = {'col1': [1, 2], 'wkt': [pgon1, pgon2]}
df = pd.DataFrame( data=d )

# make geo-dataframe from it
geometry = [wkt.loads(pgon) for pgon in df.wkt]
gdf2 = gpd.GeoDataFrame(df, \
                   crs={'init': 'epsg:4326'}, \
                   geometry=geometry)

# plot it as red polygons
gdf2.plot(ax=ax1, color='red', zorder=5)

输出图：