如何比较两个目录并在python中输出更改的文件

Question

我在Linux中有两个目录，其中有两个文件。我需要比较这两个目录并打印出更改的文件。

folder1:
  file1.txt   file2.txt

folder2:
  file1.txt   file2.txt

我需要将folder1与folder2进行比较，并打印出这两个目录中不同的文件名。我想首先使用ls命令获取文件列表并将它们放在list中，然后使用python的filecmp进行比较，如下所示：

import os
import filecmp

folder1_path = "/home/user/folder1/"
folder2_path = "/home/user/folder2/"

def ls(path):
   all = []
   walked = os.walk(path)
   for base, sub_f, files in walked:           
       for sub in sub_f:           
            entry = os.path.join(base,sub)
            entry = entry[len(path):].strip("\\")
            all.append(entry)

       for file in files:          
           entry = os.path.join(base,file)
           entry = entry[len(path):].strip("\\")
           all.append(entry)
    all.sort()
    return all

def folder_diff(folder1_path, folder2_path):
    folder1_list = ls(folder1_path)
    folder2_list = ls(folder2_path)

    for item1, item2 in zip(folder1_list, folder2_list):
        res = filecmp.cmp(folder1_path + item1, folder2_path + item2)

data = folder_diff(folder1_path, folder2_path)
print(data)

当文件存在于两个文件夹中时，这会引发错误FileNotFound。任何人都可以建议任何更新。谢谢

Answer 1

为了只有一个功能你可以使用它：

def folder_diff():
    folder1 = os.listdir(PATH1) # folder containing your files
    folder2 = os.listdir(PATH2) # the other folder

    for item1 in folder1:
        for item2 in folder2:
            if(item1==item2):
                res = filecmp.cmp(PATH1+item1, PATH2+item2)

if __name__ == "__main__":
import os
import filecmp
PATH1 = ''
PATH2 = ''
data = folder_diff()
print(data)

Answer 2

您也可以使用glob模块完成此操作

import os
import glob
import filecmp

comparison = []
for each in glob.glob('home/user/folder1/**'):
    for each1 in glob.glob('home/user/folder2/**'):
        if os.path.basename(each) == os.path.basename(each1):
            comparison.append(filecmp.cmp(each, each1))

print(comparison)