所以我试图在Java(BlueJ)的for循环中获得一个延迟,但它向我显示错误消息:“必须捕获或声明抛出未报告的异常java.lang.interruptedexception”我在做什么错了?
public class R{
private boolean a;
private boolean b;
if(a && b){
String[]Array = {"x","y","z"};
for(int i = 0; i < Array.length; i++, Thread.sleep(1000))
{
System.out.print(Array[i]);
}}}
我希望最终结果是:
x
//delay
y
//delay
z
您需要将Thread.sleep(1000)代码放入循环中,如下所示:
for(int i = 0; i < Array.length; i++){
System.out.print(Array[i]);
Thread.sleep(1000); // if you prefer, you could put before the System.out...
}
而且我建议您使用InterruptedException异常处理封装Thread.sleep(1000)。
以下是一些示例。Java Delay/Wait