我有一个程序,该程序从文件中读取数据,并使用该数据为图形创建节点。问题是,从4行文件中,我的程序仅创建两个节点(一行应创建一个节点)。文本文件如下所示:
A/0/0.7
C/1/0/0.1 0.4
B/1/0/0.6 0.8
D/2/2 1/0.6 0.7 0.1 0.2
节点数据的结构(它是贝叶斯网络):
节点名称/父母数量/文件中父母的索引/概率
using (StreamReader reader = new StreamReader(file))
{
while ((line = reader.ReadLine()) != null)
{
line = reader.ReadLine();
string name = "";
List<int> parents = new List<int>();
List<float> probs = new List<float>();
string[] splitLine = line.Split('/');
Console.WriteLine("splitLine array: ");
foreach (string item in splitLine)
{
Console.WriteLine(item);
}
Console.WriteLine();
int index = 2;
name = splitLine[0];
if (splitLine.Length == 4)
{
string[] temp = splitLine[2].Split(' ');
foreach (string item in temp)
parents.Add(Int32.Parse(item));
index = 3;
}
string[] temp1 = splitLine[index].Split(' ');
foreach (string item in temp1)
probs.Add(float.Parse(item, CultureInfo.InvariantCulture.NumberFormat));
Node newNode = new Node(name, parents, probs);
graph.Add(newNode);
}
}
如果调用Node构造函数,程序将打印新节点具有的数据。我希望它能打印出来:
Created Node:
Name: A
Parents' indexes: 0
Probabilities: 0.7
Created Node:
Name: C
Parents' indexes: 0
Probabilities: 0.1 0.4
Created Node:
Name: B
Parents' indexes: 0
Probabilities: 0.6 0.8
Created Node:
Name: D
Parents' indexes: 2 1
Probabilities: 0.6 0.7 0.1 0.2
但是我得到:
Created Node:
Name: C
Parents' indexes: 0
Probabilities: 0.1 0.4
Created Node:
Name: D
Parents' indexes: 2 1
Probabilities: 0.6 0.7 0.1 0.2
您两次阅读了该行。
using (StreamReader reader = new StreamReader(file))
{
while ((line = reader.ReadLine()) != null) // HERE
{
line = reader.ReadLine(); // AND HERE
string name = "";
List<int> parents = new List<int>();
List<float> probs = new List<float>();
string[] splitLine = line.Split('/');
Console.WriteLine("splitLine array: ");
foreach (string item in splitLine)
{
Console.WriteLine(item);
}
Console.WriteLine();
int index = 2;
name = splitLine[0];
if (splitLine.Length == 4)
{
string[] temp = splitLine[2].Split(' ');
foreach (string item in temp)
parents.Add(Int32.Parse(item));
index = 3;
}
string[] temp1 = splitLine[index].Split(' ');
foreach (string item in temp1)
probs.Add(float.Parse(item, CultureInfo.InvariantCulture.NumberFormat));
Node newNode = new Node(name, parents, probs);
graph.Add(newNode);
}
}
您两次致电reader.ReadLine()
:
while ((line = reader.ReadLine()) != null) // <-- First here
{
line = reader.ReadLine(); // <-- Again here
只需删除第二个line = reader.ReadLine()
,所以您的代码是:
...
while ((line = reader.ReadLine()) != null)
{
string name = "";
List<int> parents = new List<int>();
...