尝试/捕获/最终使用ESLint预期在异步箭头功能的末尾返回一个值

Question

我的代码中出现此ESLint错误：

function（productId：any）：承诺预期在异步箭头功能的末尾返回一个值]

export const getGooglePlayPayment = async (productId) => {
  await InAppBilling.close();
  try {
    await InAppBilling.open();

    if (!await InAppBilling.isSubscribed(productId)) {
      const details = await InAppBilling.subscribe(productId);
      console.log('You purchased: ', details);
      return details.purchaseState === PAYMENT_STATE.PurchasedSuccessfully;
    }
  } catch (err) {
    console.log(err);
    return false;
  } finally {
    await InAppBilling.consumePurchase(productId);
    await InAppBilling.close();
  }
};

有人可以帮助我解决此问题，而不必禁用ESLing规则：）

感谢

Answer 1

如果未满足if块中的try语句，则不会返回任何内容。如果isSubscribed调用为真，则应返回一些内容：

export const getGooglePlayPayment = async (productId) => {
  await InAppBilling.close();
  try {
    await InAppBilling.open();

    if (!await InAppBilling.isSubscribed(productId)) {
      const details = await InAppBilling.subscribe(productId);
      console.log('You purchased: ', details);
      return details.purchaseState === PAYMENT_STATE.PurchasedSuccessfully;
    }
    return 'Already subscribed';
  } catch (err) {
    console.log(err);
    return false;
  } finally {
    await InAppBilling.consumePurchase(productId);
    await InAppBilling.close();
  }
};

（（当然，将Already subscribed替换为最有意义的内容。如果您只是想表明交易成功，也许是return true。重要的是将其与return false中的catch区别开]。）