coinbase api client.get_accounts() 不返回所有钱包

问题描述 投票:0回答:2

目前,coinbase api 无法获取我的 Atom 钱包。通过其他测试代码,我可以看到它返回了 94 个钱包,但它们都不是我的 Atom 钱包,而且帐户数据甚至看起来都没有 94 个元素。

关于如何显示我的原子钱包有什么想法吗?我尝试了 client.get_accounts(limit=200) 技巧但没有成功。

#import coinbase api
from coinbase.wallet.client import Client

# Coinbase Credentials
api_key = 'xxx'
api_secret = 'xxx'

# create a coinbase client
cb_client = Client(api_key, api_secret)
cb_accounts = cb_client.get_accounts()

# coin setting
coin = 'ATOM'

#print accounts
print(cb_accounts)

#get coin balance
for i in cb_accounts['data']:
    if i['currency'] == coin:
        coin_balance = float(i['native_balance']['amount'])

#print coin balance
print(coin_balance)

返回样本数据:

{
  "data": [
    {
      "allow_deposits": true,
      "allow_withdrawals": true,
      "balance": {
        "amount": "0.00000000",
        "currency": "FET"
      },
      "created_at": "xxx",
      "currency": "FET",
      "id": "xxx",
      "name": "FET Wallet",
      "native_balance": {
        "amount": "0.00",
        "currency": "USD"
      },
      "primary": false,
      "resource": "account",
      "resource_path": "xxx",
      "type": "wallet",
      "updated_at": "xxx"
    }
  ]
}
python coinbase-api
2个回答
4
投票

更好的方法是使用 coinbase api 分页参数:

#iniliase next wallet id 
next = None
# this loop will run until the next_uri parameter is none ( it means that there is no other page to show)
while True:
   accounts = client.get_accounts(starting_after=next)
   next = accounts.pagination.next_starting_after
   print(accounts.data)
   if accounts.pagination.next_uri == None :
     print("end")
     break

如果您喜欢脚本打印零余额的钱包,请尝试以下操作:

#iniliase next wallet id 
next=None
# this loop wil run until next_uri parameter is none ( it means that there is no other page to show)
while True:
   accounts=client.get_accounts(starting_after=next)
   next=accounts.pagination.next_starting_after
   for wallet in accounts.data:
      if wallet['native_balance']['amount'] != '0.00':
         print(str(wallet['name']) + ' ' + str(wallet['native_balance']))
   if accounts.pagination.next_uri==None :
     print("end")
     break

0
投票

有人知道为什么我无法使用这种获取帐户的确切方式获得

native_balance
密钥吗?

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