下次单击操作时,使下一个EditText显示在屏幕上

问题描述 投票:1回答:3

我的屏幕上有几个EditTexts,它们都是按照以下方式构建的。

XML:

<android.support.design.widget.TextInputEditText
            android:id="@+id/textInputEditText"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="@string/name"
            app:fontFamily="@font/karla"
            android:inputType="textMultiLine|textCapCharacters"
            android:maxLength="12"
            android:textColor="#5C7264"
            />

码:

private void addItemsToLinearLayout(int numItems) {

 LayoutInflater inflater = LayoutInflater.from(mContext);

     for (int i = 0; i < numItems; i++) {

         View childView = inflater.inflate(R.layout.item_linearlayout, null);        

         linearlayoutPlayersNames.addView(childView);            

         ImageView deleteRowIcon = childView.findViewById(R.id.deleteRowIcon);     
         deleteRowIcon.setOnClickListener(this);

         TextView myTV = childView.findViewById(R.id.txtTitle);          
         myTV.setText(String.format(getString(R.string.player), linearlayoutPlayersNames.indexOfChild(childView) + 1));         


         EditText editText = childView.findViewById(R.id.textInputEditText);
         editText.setImeOptions(EditorInfo.IME_ACTION_NEXT);
         editText.setRawInputType(InputType.TYPE_TEXT_FLAG_CAP_CHARACTERS);

    }
}

当我单击软键盘的下一个按钮时,它会按预期移动到下一个EditText,但仅在屏幕上显示下一个EditText时。当下一个EditText在屏幕上不可见时,下一个动作无效,并且最重要的是,它将下一个动作按钮更改为回车动作按钮,如下视频所示:https://imgur.com/a/snAbdmU

我打算做的是单击下一步按钮并将可见性移动到下一个EditText。

更新:有些人告诉我使用android:nextFocusDown或使用editText.setNextFocusForwardId(editTextSecond.getId());以编程方式执行此操作,但我不能,因为我使用循环来创建EditTexts,如代码中所示。

android android-edittext android-softkeyboard android-inputtype
3个回答
0
投票

做这个 :

  EditText editText2 = childView.findViewById(R.id.textInputEditText);
  EditText editText = childView.findViewById(R.id.textInputEditText);
  editText.setOnEditorActionListener(new EditText.OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            boolean handled = false;
            if (actionId == EditorInfo.IME_ACTION_DONE) {
        editText2.setVisibility(View.VISIBLE);
        editText2.setImeOptions(EditorInfo.IME_ACTION_NEXT);
        editText2.setRawInputType(InputType.TYPE_TEXT_FLAG_CAP_CHARACTERS);
              return handled;
             }
        }
    });

  editText2.setOnEditorActionListener(new EditText.OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            boolean handled = false;
            if (actionId == EditorInfo.IME_ACTION_DONE) {
               // do same for others to    
            return handled;  
             }

        }
    });

0
投票

是的,您需要从textMultiLine中删除android:inputType然后它将适用于下一个EditText可见且不可见的情况。

<android.support.design.widget.TextInputEditText
        android:id="@+id/textInputEditText"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:hint="@string/name"
        app:fontFamily="@font/karla"
        android:inputType="textCapCharacters"
        android:maxLength="12"
        android:textColor="#5C7264"
        />

0
投票

正如你所提到的那样,你是以编程方式而不是在xml中使用它

android:nextFocusDown="@id/textInputEditTextSecond"

您可以像这样以编程方式使用它

editText.setNextFocusForwardId(editTextSecond.getId());

并为所有EditText添加editText.setImeOptions(EditorInfo.IME_ACTION_NEXT);

在每个EditText的循环setId内部,然后设置nextForward,如下所示

private void addItemsToLinearLayout(int numItems) {

 LayoutInflater inflater = LayoutInflater.from(mContext);

     for (int i = 0; i < numItems; i++) {

         View childView = inflater.inflate(R.layout.item_linearlayout, null);        

         linearlayoutPlayersNames.addView(childView);            

         ImageView deleteRowIcon = childView.findViewById(R.id.deleteRowIcon);     
         deleteRowIcon.setOnClickListener(this);

         TextView myTV = childView.findViewById(R.id.txtTitle);          
         myTV.setText(String.format(getString(R.string.player), linearlayoutPlayersNames.indexOfChild(childView) + 1));         


         EditText editText = childView.findViewById(R.id.textInputEditText);
         editText.setImeOptions(EditorInfo.IME_ACTION_NEXT);
         editText.setRawInputType(InputType.TYPE_TEXT_FLAG_CAP_CHARACTERS);

         // setId of each EditText and then set nextForward as
         editText.setId(i);
         editText.setNextFocusForwardId(i+1);

    }
}
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