我有一个排序算法的问题,包括对子类Priority Person的对象进行排序(这些对象将被放置在一个列表中,目标是改变子类priority person的lt方法,以影响列表中的.sort()方法)。 sort()方法的影响),如果一个Priority Person的对象有一个参数True描述的缺陷,它应该被认为比一个得到参数False的优先级人对象的缺陷少(这意味着这个人没有任何缺陷),如果两者都有缺陷或两者都没有缺陷,应该考虑所涉及的优先级人的名字的词法顺序。优先人的子类的主类就是我上面展示的类Person 。
class Person(object):
def __init__(self, name):
"""Create a person"""
self.name = name
try:
lastBlank = name.rindex(' ')
self.lastName = name[lastBlank + 1:]
except:
self.lastName = name
self.birthday = None
def __lt__(self, other):
"""Returns True if self's name is lexicographically
less than other's name, and False otherwise"""
return self.name < other.name
def __str__(self):
"""Returns self's name"""
return self.name
class PriorityPerson(Person): # the __lt__ part of this class does not work and I don't know why?
def __init__(self,name,deficiencia):
super().__init__(name)
self.deficiente = deficiencia
def __lt__(self, other):
if self.deficiente and other.deficiente and self.name< other.name:
return self.name < other.name
elif self.deficiente and other.deficiente and other.name < self.name:
return other.name< self.name
elif self.deficiente and not other.deficiente and self.name < other.name:
return self.name < other.name
elif self.deficiente and not other.deficiente and other.name < self.name:
return self.name< other.name
elif not self.deficiente and other.deficiente and self.name < other.name:
return other.name < self.name
elif not self.deficiente and other.deficiente and other.name < self.name:
return other.name < self.name
elif not self.deficiente and not other.deficiente and self.name < other.name:
return self.name < other.name
elif not self.deficiente and not other.deficiente and other.name < self.name:
return other.name < self.name
实施例。
p1 = PriorityPerson("John Smith", False)
p2 = PriorityPerson("Sam Mendes", False)
p3 = PriorityPerson("Grandmother Anne", True)
p4 = PriorityPerson("Stephen Hawking", True)
p5 = PriorityPerson("Betty Large", True)
listaPessoas = [p1,p2,p3,p4, p5]
listaPessoas.sort()
for p in listaPessoas:
print(p)
正确的输出 :
Betty Large
Grandmother Anne
Stephen Hawking
John Smith
Sam Mendes
我的错误输出 。
Betty Large
Stephen Hawking
Grandmother Anne
Sam Mendes
John Smith
任何帮助都将是非常感激的.谢谢你.
我希望这个问题能解决
class Person(object):
def __init__(self, name):
"""Create a person"""
self.name = name
try:
lastBlank = name.rindex(' ')
self.lastName = name[lastBlank + 1:]
except:
self.lastName = name
self.birthday = None
def __lt__(self, other):
"""Returns True if self's name is lexicographically
less than other's name, and False otherwise"""
return self.name < other.name
def __str__(self):
"""Returns self's name"""
return self.name
class PriorityPerson(Person):
def __init__(self, name, deficiencia):
super().__init__(name)
self.deficiente = deficiencia
def __lt__(self, other):
if self.deficiente and not other.deficiente:
# If self is VIP and other is not, just return True
return True
elif not self.deficiente and other.deficiente:
# If other is VIP and self is not, just return False
return False
# On equal priority, normal compare
return super().__lt__(other)
p1 = PriorityPerson("John Smith", False)
p2 = PriorityPerson("Sam Mendes", False)
p3 = PriorityPerson("Grandmother Anne", True)
p4 = PriorityPerson("Stephen Hawking", True)
p5 = PriorityPerson("Betty Large", True)
listaPessoas = [p1,p2,p3,p4, p5]
listaPessoas.sort()
for p in listaPessoas:
print(p)
的输出。
Betty Large
Grandmother Anne
Stephen Hawking
John Smith
Sam Mendes
基本上是按优先级排序,其次是按名字排序。所以,你必须先比较不同的优先级,然后才比较相同优先级的名字。
def __lt__(self, other):
if self.deficiente != other.deficiente: # yes, you can compare bools!
return self.deficiente
else:
return self.name < other.name