组件不对嵌套的mobx商店做出反应

问题描述 投票:0回答:1

我在MobX中渲染一个基于嵌套商店(SquareModel)的正方形。当点击方块时,我想在SquareModel内开火,改变一个selected属性,这反过来会调整方块的大小。但是,我似乎无法让广场对房产变化做出反应。关于如何使这个工作的任何想法?

沙箱:https://codesandbox.io/s/m51oyzz069

MainStore:

import { observable, decorate } from "mobx";
import SquareModel from "./SquareModel";

class MobXStore {
  square = new SquareModel();
}

decorate(MobXStore, {
  square: observable
});

export default new MobXStore();

NestedStore:

import { observable, action, decorate } from "mobx";

class SquareModel {
  selected = false;
  toggleSelection() {
    console.log("toggle selection");
    this.selected = !this.selected;
  }
}

decorate(SquareModel, {
  selected: observable,
  toggleSelection: action
});

export default SquareModel;

阵营:

const App = observer(() => {
  return (
    <svg className="App">
      <svg x={100} y={100}>
        <Square
          unit={MobXStore.square.selected ? 2 : 1}
          onPointerUp={MobXStore.square.toggleSelection}
        />
      </svg>
    </svg>
  );
});

export const Square = observer(({ unit, ...props }) => {
  console.log("render square");
  return (
    <g {...props}>
      <rect height={unit * 50} width={unit * 50} style={{ fill: "blue" }} />
    </g>
  );
});
mobx mobx-react
1个回答
1
投票

toggleSelection方法中存在“this”错误

它应该看起来像:

onPointerUp = {() => MobXStore.square.toggleSelection()}

或者你需要在这里使用箭头功能:

toggleSelection = () => {
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