MySQL Prepared语句在子查询[重复]中返回意外记录

Question

此问题已经在这里有了答案：

• mysqli bind_param for array of strings6个答案
• I have an array of integers, how do I use each one in a mysql query (in php)?5个答案

我有下面的代码可以提取所有记录。

$item_ids = [6, 7];
$conn = mysqli_connect("localhost", "root", "", "test");
$comma_seperated_item_ids = implode(",", $item_ids);

$stmt = $conn->prepare("select price, quantity from b_sales_item where id in (?)");
$stmt->bind_param("s", $comma_seperated_item_ids);
$stmt->execute();
$result = $stmt->get_result();

while ($sales = $result->fetch_assoc()) {
    echo "<pre>";
    print_r($sales);
    echo "</pre>";
}           

上面的代码仅输出一条记录，我希望是2。

如果我从]更改下面的代码，一切正常

$stmt = $conn->prepare("select price, quantity from b_sales_item where id in (?)");
$stmt->bind_param("s", $comma_seperated_item_ids);
to

$stmt = $conn->prepare("select price, quantity from b_sales_item where id in (6,7)");
//$stmt->bind_param("s", $comma_seperated_item_ids);
我是否缺少任何内容来输出2条记录？

我有下面的代码可提取所有记录。 $ item_ids = [6，7]; $ conn = mysqli_connect（“ localhost”，“ root”，“”，“ test”）; $ comma_seperated_item_ids = implode（“，”，$ item_ids）; $ stmt = $ conn-＆...

Answer 1

如果您执行以下操作