具有参数和值的条件构造

Question

请考虑以下代码。如果我删除了eval而只写了if "$1"，则它不起作用。是否可以摆脱eval？

assert () {
  if eval "$1"      #Is it possible to get rid of the eval?
  then
    echo "Assertion OK:  \"$1\""
  else
    echo "Assertion FAILED:  \"$1\""
  fi
}

assert " [[ /tmp/a = /tmp/* ]]"

Answer 1

将括号扔掉，然后输入并完成

#!/bin/bash

assert () {

  if [[ $1 ]]
  then
    echo "Assertion OK:  \"$1\""
  else
    echo "Assertion FAILED:  \"$1\""
  fi
}

assert " /tmp/a = /tmp/* "