为什么安全的Spring WS集成会返回未经授权的[401]?

问题描述 投票:1回答:1

我正在Spring引导中使用安全的第三方SOAP Web服务,并且正在关注Spring WS以及描述安全集成Spring WS - HTTPS Client-Server Example的在线资源。在资源文件夹下找到证书.cer和.jks文件后,并使用此代码包装了我的配置:

@Configuration
public class WSGeneralConfig {

    @Autowired
    @Qualifier("WifiTouristConfig")
    CredentailsConfig wifiTouristConfig;

    @Autowired
    @Qualifier("TradeinWSConfig")
    CredentailsConfig tradeinWSConfig;

    @Autowired
    ClientInterceptor[] interceptors;

    @Bean
    public WifiToursitWrapper wifiToursitWrapper(@Value("${tibco.wifi.tourist.url}") String uri) throws Exception {
        WifiToursitWrapper wifiToursitWrapper = new WifiToursitWrapper();
        Jaxb2Marshaller marshaller = new Jaxb2Marshaller();
        marshaller.setContextPath("com.usp.tibco.wifi");
        wifiToursitWrapper.setMarshaller(marshaller);
        wifiToursitWrapper.setUnmarshaller(marshaller);
        wifiToursitWrapper.setDefaultUri(uri);
        wifiToursitWrapper.setInterceptors(interceptors);
        wifiToursitWrapper.setMessageSender(
                httpComponentsMessageSender(wifiTouristConfig.getUsername(), wifiTouristConfig.getPassword()));
        return wifiToursitWrapper;
    }

    public HttpComponentsMessageSender httpComponentsMessageSender(String userName, String password) throws Exception {
        HttpComponentsMessageSender httpComponentsMessageSender = new HttpComponentsMessageSender();
        httpComponentsMessageSender.setCredentials(new UsernamePasswordCredentials(userName, password));
        httpComponentsMessageSender.setHttpClient(httpClient());
        httpComponentsMessageSender.setAuthScope(AuthScope.ANY);
        httpComponentsMessageSender.afterPropertiesSet();
        return httpComponentsMessageSender;
    }

    public HttpClient httpClient() throws Exception {
        return HttpClientBuilder
                .create()
                .setSSLSocketFactory(new SSLConnectionSocketFactory(sslContext(), NoopHostnameVerifier.INSTANCE))
                .addInterceptorFirst(new RemoveSoapHeadersInterceptor()).build();
    }


    public SSLContext sslContext() throws Exception {
        File file = new ClassPathResource("cert/cacerts.jks").getFile();
        return SSLContextBuilder.create().loadTrustMaterial(file, "jksPassword".toCharArray()).build();
    }
}

客户端类也这样

public class WifiToursitWrapper extends WebServiceGatewaySupport {

    @SoapOperationName(systemName = SystemName.TIBCO, operationName = "RegisterByIntlNo")
    public RegisterByIntlNoResponse registerByIntlNo(RegisterByIntlNoRequest request) {
        return (RegisterByIntlNoResponse) getWebServiceTemplate().marshalSendAndReceive(request,
                message -> ((SoapMessage) message)
                        .setSoapAction("/RegisterByIntlNo"));
    }
}

不幸的是,我得到了未经授权的例外,但我不知道其根本原因是什么?这是异常堆栈跟踪的快照

org.springframework.ws.client.WebServiceTransportException: Unauthorized [401]
    at org.springframework.ws.client.core.WebServiceTemplate.handleError(WebServiceTemplate.java:699)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:609)
    at org.springframework.ws.client.core.WebServiceTemplate.sendAndReceive(WebServiceTemplate.java:555)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:390)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:383)
    at com.etisalat.account.wrapper.WifiToursitWrapper.registerByIntlNo(WifiToursitWrapper.java:25)
spring spring-boot spring-security spring-ws
1个回答
1
投票

我通过在请求中添加基本身份验证解决了这个问题,在这个问题的答案Consuming SOAP WS returns Error 401 unauthorized的很好帮助下,我为我的情况更改了一些代码。

private HttpComponentsMessageSender httpComponentsMessageSender(String userName, String password) throws Exception {
        HttpComponentsMessageSender httpComponentsMessageSender = new HttpComponentsMessageSender();
        httpComponentsMessageSender.setHttpClient(httpClient(userName, password));
        return httpComponentsMessageSender;
    }

    private HttpClient httpClient(String username, String password) throws Exception {
        List<Header> headers = new ArrayList<>();
        BasicHeader authHeader = new BasicHeader("Authorization", "Basic " + base64authUserPassword(username, password));
        headers.add(authHeader);
        RequestDefaultHeaders reqHeader = new RequestDefaultHeaders(headers);
        return HttpClientBuilder.create()
                .setSSLSocketFactory(new SSLConnectionSocketFactory(sslContext(), NoopHostnameVerifier.INSTANCE))
                .addInterceptorFirst(new RemoveSoapHeadersInterceptor()).addInterceptorLast(reqHeader).build();
    }

    private String base64authUserPassword(String username, String password) {
        String userpassword = username + ":" + password;
        String encodedAuthorization = new String(Base64.getEncoder().encode(userpassword.getBytes()));
        return encodedAuthorization;
    }
© www.soinside.com 2019 - 2024. All rights reserved.