镜头和TypeFamilies

问题描述 投票:3回答:2

我遇到了使用Control.Lens的问题 使用-XTypeFamilies GHC编译指示时的数据类型。

{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE TypeFamilies    #-}

import Control.Lens (makeLenses)

class SomeClass t where
  data SomeData t :: * -> *

data MyData = MyData Int

instance SomeClass MyData where
  data SomeData MyData a = SomeData {_a :: a, _b :: a}

makeLenses ''SomeData

错误消息是:reifyDatatype: Use a value constructor to reify a data family instance

有没有办法克服它,也许使用Control.Lens的一些功能?

haskell lens template-haskell type-families lenses
2个回答
3
投票

最明智的事情就是自己定义这些镜片......这不是很难:

a, b :: Lens' (SomeData MyData a) a
a = lens _a (\s a' -> s{_a=a'})
b = lens _b (\s b' -> s{_b=b'})

甚至

a, b :: Functor f => (a -> f a) -> SomeData MyData a -> f (SomeData MyData a)
a f (SomeData a₀ b₀) = (`SomeData`b₀) <$> f a₀
b f (SomeData a₀ b₀) =   SomeData a₀  <$> f b₀

...根本不使用镜头库中的任何东西,但与所有镜头组合器完全兼容。


1
投票

tfMakeLenses为关联的数据类型生成t a -> a -> t a类型的setter。 有些地方可以改进这个功能,但它有效!

tfMakeLenses :: Name -> DecsQ
tfMakeLenses t = do
  fieldNames <- tfFieldNames t
  let associatedFunNames = associateFunNames fieldNames
  return (map createLens associatedFunNames)
  where createLens :: (Name, Name) -> Dec
        createLens (funName, fieldName) =
          let dtVar  = mkName "dt"
              valVar = mkName "newValue"
              body   = NormalB (LamE [VarP valVar] (RecUpdE (VarE dtVar) [(fieldName, VarE valVar)]))
          in FunD funName [(Clause [VarP dtVar] body [])]

        associateFunNames :: [Name] -> [(Name, Name)]
        associateFunNames [] = []
        associateFunNames (fieldName:xs) = ((mkName . tail . nameBase) fieldName, (mkName . nameBase) fieldName)
                                         : associateFunNames xs

        tfFieldNames t = do
          FamilyI _ ((DataInstD _ _ _ _ ((RecC _ fields):_) _):_) <- reify t
          let fieldNames = flip map fields $ \(name, _, _) -> name
          return fieldNames
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