Mysql Self Join在同一表中查找父子关系

问题描述 投票:3回答:2

我正在尝试计算某个时期内一匹雄性赛马(雄性)的所有后代所赢得的金额。由父亲列出,赢得最多的钱。我运行查询并遇到一个问题后得到结果Im,我无法显示父亲姓名,仅显示其ID。

SELECT  `horses`.`SireID` AS  `SireID` , `horses`.`HorseName` AS  `Sire Name`, 
                  COUNT(  `runs`.`HorsesID` ) AS  `Runs` , 
                  COUNT( 
                           CASE WHEN  `runs`.`Finish` =1
                                THEN 1 
                                ELSE NULL 
                                END ) AS  `Wins` , 
                  CONCAT( FORMAT( (
                                COUNT( 
                                       CASE WHEN  `runs`.`Finish` =1
                                            THEN 1 
                                            ELSE NULL 
                                            END ) / COUNT
                                    (  `runs`.`TrainersID` ) ) *100, 0 ) ,  '%'
                  ) AS  `Percent` , 
           FORMAT( SUM(  `runs`.`StakeWon` ) , 0 ) AS  `Stakes` 
FROM runs
INNER JOIN horses ON runs.HorsesID = horses.HorsesID
INNER JOIN races ON runs.RacesID = races.RacesID
WHERE  `races`.`RaceDate` >= STR_TO_DATE(  '2012,07,01',  '%Y,%m,%d' ) 
AND  `races`.`RaceDate` < STR_TO_DATE(  '2012,07,01',  '%Y,%m,%d' ) + INTERVAL 1 
MONTH 
AND `horses`.`SireID`  <> `horses`.`HorsesID`
GROUP BY  `horses`.`SireID`, `horses`.`HorseName`
ORDER BY SUM(  `runs`.`StakeWon` ) DESC

例如,在马表中进行记录,一匹马有一个horsesID,而他们也有一个sireID(他们的父亲)。 sireID在同一表的另一条记录中具有等效的horsesID,因为它也是一匹马

基本上我需要将horseName映射到sireID。

我以为自我加入会奏效。

 `AND `horses`.`SireID`  <> `horses`.`HorsesID`` 

但是它没有返回与SireID相对应的正确Sire名称。

mysql sql self-join
2个回答
8
投票

您可以在表本身上进行JOIN。这是一个更简单的示例:

SELECT Horses.HorseID, Horses.HorseName, Horses.SireID, b.HorseName as SireName
FROM Horses
LEFT JOIN Horses b ON (Horses.SireID = b.HorseID)

您可能可以从这里弄清楚如何添加条件。


1
投票
join horses sires on sires.HorsesID = horses.SireID
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