我无法将我的php连接到我的html表单。表单操作不起作用

问题描述 投票:0回答:1

我创建了一个简单的消息表单,并且每当我对其进行测试时,该表单操作似乎都不起作用。它只会导致我进入错误页面

<div class="form">
    <form action="connect.php" method="post">
        <input id="name" name="name" type="text" class="form-control" placeholder="Your Name" required>
        <br>
        <textarea name="message" id="message" class="form-control message" placeholder="Message" rows="4" required></textarea> <br>
        <input type="submit" class="form-control submit" value="SEND MESSAGE" name="submit">
    </form>
</div>

这里是PHP

<?php

    $name = $_POST['name'];
    $message = $_POST['message'];

    $conn = new mysqli ('localhost','root','','messg');
    if($conn->connect_error){
        die('Connection Failed : ' .$conn->connect_error);

    }else{

        $stmt = $conn->prepare("insert into mesages(name, message) values(?, ?)");
        $stmt->bind_param("ss",$name, $message);

        $stmt->execute();

        echo "Message Sent!";

        $stmt->close();
        $conn->close();
    }

?>  
php html mysql forms
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