我创建了一个简单的消息表单,并且每当我对其进行测试时,该表单操作似乎都不起作用。它只会导致我进入错误页面
<div class="form">
<form action="connect.php" method="post">
<input id="name" name="name" type="text" class="form-control" placeholder="Your Name" required>
<br>
<textarea name="message" id="message" class="form-control message" placeholder="Message" rows="4" required></textarea> <br>
<input type="submit" class="form-control submit" value="SEND MESSAGE" name="submit">
</form>
</div>
这里是PHP
<?php
$name = $_POST['name'];
$message = $_POST['message'];
$conn = new mysqli ('localhost','root','','messg');
if($conn->connect_error){
die('Connection Failed : ' .$conn->connect_error);
}else{
$stmt = $conn->prepare("insert into mesages(name, message) values(?, ?)");
$stmt->bind_param("ss",$name, $message);
$stmt->execute();
echo "Message Sent!";
$stmt->close();
$conn->close();
}
?>
超文本传输协议(HTTP)405不允许的方法