我需要帮助来计算频率和百分比，我需要按最频繁的顺序使用，并且没有引号和花括号等

Question

[到目前为止，我一直在使用网站来计算频率，但是它们最多可以包含50,000个字符，现在我需要自己做，这实际上是我从一开始就应该做的。

   let frequencyCount = Dictionary(grouping: numbers) { $0 }
        .mapValues{ $0.count }

   mostFrequentTextView.text = String(format:"%@", frequencyCount)


   let numbers = [

    "1, 2, 3, 4",
    "5, 6, 7, 8",
    "3, 4, 5, 6",
    "1, 2, 7, 8",
    "1, 2, 3, 4",
    "3, 4, 5, 6",
    "1, 2, 3, 4",
    "1, 2, 3, 4",
    "5, 6, 7, 8",
    "3, 4, 5, 6",
    "1, 2, 7, 8",
    "1, 2, 3, 4",
    "3, 4, 5, 6",
    "1, 2, 3, 4" ]

//当前结果↓

          {
     "1, 2, 3, 4" = 6;
     "1, 2, 7, 8" = 2;
     "3, 4, 5, 6" = 4;
     "5, 6, 7, 8" = 2;
          }

//所需结果↓

      1, 2, 3, 4   X 6   43%

      3, 4, 5, 6   X 4   29%

      1, 2, 7, 8   X 2   14%

      5, 6, 7, 8   X 2   14%

Answer 1

一旦分组，就可以使用sorted和reduce建立输出

let output = frequencyCount.sorted(by: {$0.value > $1.value}).reduce(into: "") {
    let fraction =  Int(round(100.0 * Double($1.value) / Double(numbers.count)))
    $0 += "\($1.key)   X \($1.value)  \(fraction)%\n"
}

输出

1, 2, 3, 4   X 6  43%  
3, 4, 5, 6   X 4  29%  
1, 2, 7, 8   X 2  14%  
5, 6, 7, 8   X 2  14%

如果您喜欢String.format()

let fraction = round(100.0 * Double($1.value) / Double(numbers.count))
$0 += String(format: "%@   X %d  %.0f%%\n", $1.key, $1.value, fraction)

---

如果您想将所有内容放在一起，则填写代码

let total = Double(numbers.count)
let output = Dictionary(grouping: numbers) { $0 }
    .mapValues{ $0.count }
    .sorted(by: {$0.value > $1.value})
    .reduce(into: "") {
        $0 += "\($1.key)   X \($1.value)  \(Int(round(100.0 * Double($1.value) / total)))%\n"
    }