Oracle 10g：聚合

问题描述 投票：1回答：2

得到以下表格：

表T.

DATE_A    | DATE_B    | ERRCODE 
----------+-----------+--------
01/MAY/13 | 01/JUN/15 | X
01/DEC/17 | 01/FEB/18 | Y

表U.

ERRCODE | ERRDESC
--------+-------------------------------------------
X       | Conflicting from : {1} and to Period : {2}
Y       | Periods : {1} and {2} overlap

以下代码：

select period, wm_concat(errcode) as issues
from ((select DATE_A as period, errcode from T where DATE_A is not null) union all
      (select DATE_B, errcode from T where DATE_B is not null)
     ) di
group by period
order by period;

将改变Table T如下：

PERIOD    | ISSUES
----------+--------
01/MAY/13 | X
01/JUN/15 | X
01/DEC/17 | Y
01/FEB/18 | Y

我想转换上面的代码，以便：

  • 它将T表中的ERRCODE替换为表ERRDESC中相应的U
  • 分别用{1}和{2}替换ERRDESC中的DATE_A和DATE_B
  • 将结果插入Table V

所以我尝试了这个：

INSERT INTO v (
    period,
    issues
)
    SELECT
        period,
        wm_concat(issue) AS issues
    FROM
        (
            SELECT
                t.date_a AS period,
                replace( (
                    SELECT
                        u.errdesc AS issue
                    FROM
                        u
                    WHERE
                        t.errcode = u.errcode
                ),'{1}', t.date_a) AS issue
            FROM
                t
            WHERE
                t.date_a IS NOT NULL
            UNION ALL
            SELECT
                t.date_b,
                replace( (
                    SELECT
                        u.errdesc AS issue
                    FROM
                        u
                    WHERE
                        t.errcode = u.errcode
                ),'{2}', t.date_b)
            FROM
                t
            WHERE
                t.date_b IS NOT NULL
        ) di
    GROUP BY
        period;

但是我得到了这个（Table V）：

PERIOD    | ISSUES
----------+--------
01/MAY/13 | Conflicting from : 01/MAY/13 and to Period : {2}
01/JUN/15 | Conflicting from : {1} and to Period : 01/JUN/15
01/DEC/17 | Periods : 01/DEC/17 and {2} overlap
01/FEB/18 | Periods : {1} and 01/FEB/18 overlap

而不是我正在寻找的结果（Table V）：

PERIOD    | ISSUES
----------+--------
01/MAY/13 | Conflicting from : 01/MAY/13 and to Period : 01/JUN/15
01/JUN/15 | Conflicting from : 01/MAY/13 and to Period : 01/JUN/15
01/DEC/17 | Periods : 01/DEC/17 and 01/FEB/18 overlap
01/FEB/18 | Periods : 01/DEC/17 and 01/FEB/18 overlap

原因是联盟之前的选择都不知道关于date_b和选择之后不知道date_a。

题

应如何修改最新代码以获得预期结果？

注意

CREATE TABLE T
   (     
    "DATE_A" DATE, 
    "DATE_B" DATE, 
    "ERRCODE" VARCHAR2(2)
   )  ;

Insert into T (DATE_A,DATE_B,ERRCODE) values (to_date('01/MAY/13','DD/MON/RR'),to_date('01/JUN/15','DD/MON/RR'),'X');
Insert into T (DATE_A,DATE_B,ERRCODE) values (to_date('01/DEC/17','DD/MON/RR'),to_date('01/FEB/18','DD/MON/RR'),'Y');

CREATE TABLE U
   (     
    "ERRCODE"  VARCHAR2(2), 
    "ERRDESC"  VARCHAR2(100)
   )  ;

Insert into U (ERRCODE, ERRDESC) values ('X','Conflicting from : {1} and to Period : {2}');
Insert into U (ERRCODE, ERRDESC) values ('Y','Periods : {1} and {2} overlap');

CREATE TABLE V
   (     
    "PERIOD"  DATE, 
    "ISSUES"  VARCHAR2(100)
   )  ;

commit;
sql oracle10g
2个回答
2
投票

我这样做的方法是首先连接两个表并填充错误描述列中的值，然后将其拆分为两行，如下所示：

INSERT INTO v (period, issues)
WITH t AS (SELECT to_date('01/05/2013', 'dd/mm/yyyy') date_a, to_date('01/06/2015', 'dd/mm/yyyy') date_b, 'X' errcode FROM dual UNION ALL
           SELECT to_date('01/12/2017', 'dd/mm/yyyy') date_a, to_date('01/02/2018', 'dd/mm/yyyy') date_b, 'Y' errcode FROM dual),
     u AS (SELECT 'X' errcode, 'Conflicting from : {1} and to Period : {2}' errdesc FROM dual UNION ALL
           SELECT 'Y' errcode, 'Periods : {1} and {2} overlap' errdesc FROM dual),
 dummy AS (SELECT LEVEL rn FROM dual CONNECT BY LEVEL <= 2),
   res AS (SELECT t.date_a,
                  t.date_b,
                  REPLACE(REPLACE(u.errdesc, '{1}', to_char(t.date_a, 'dd/MON/yyyy', 'nls_date_language = english')), '{2}', to_char(t.date_b, 'dd/MON/yyyy', 'nls_date_language = english')) errdesc
           FROM   t
                  INNER JOIN u ON t.errcode = u.errcode)
SELECT CASE WHEN d.rn = 1 THEN res.date_a
            WHEN d.rn = 2 THEN res.date_b
       END period,
       errdesc
FROM   res
       CROSS JOIN dummy d
ORDER BY res.date_a, d.rn;

PERIOD      ERRDESC
----------- --------------------------------------------------------------------------------
01/05/2013  Conflicting from : 01/MAY/2013 and to Period : 01/JUN/2015
01/06/2015  Conflicting from : 01/MAY/2013 and to Period : 01/JUN/2015
01/12/2017  Periods : 01/DEC/2017 and 01/FEB/2018 overlap
01/02/2018  Periods : 01/DEC/2017 and 01/FEB/2018 overlap

这是一种不透明的东西;如果你在11g或以上，你将能够利用UNPIVOT命令将行分成两部分。它的工作原理是创建一个虚拟子查询，其中包含您要为每个输入行输出所需的行数 - 在您的情况下，为2。

然后我们可以将它连接到主结果集，这意味着行是重复的。然后，只需要确定每行显示哪些列，瞧！

关于日期的几个注释：

  • 请始终明确地将日期转换为字符串，而不是依赖于nls_date_format设置;您在会话中可能拥有的内容可能与其他人完全不同。
  • 年有四位数。请不要使用2位数字并强制Oracle猜测，特别是当您事先知道这些信息时！使用“RR”格式掩码可能会出现意外结果。
0
投票

使用简单的解决方案（下面）：

INSERT INTO v (
    period,
    issues
)
    SELECT
        period,
        wm_concat(issue) AS issues
    FROM
        (
            SELECT
                date_a AS period,
                replace(replace( (
                    SELECT 
                        u.errdesc AS issue
                    FROM
                        u
                    WHERE
                        t.errcode = u.errcode
                ),'{1}',t.date_a),'{2}',t.date_b) AS issue
            FROM
                t
            WHERE
                date_a IS NOT NULL
            UNION ALL
            SELECT
                date_b,
                replace(replace( (
                    SELECT 
                        u.errdesc AS issue
                    FROM
                        u
                    WHERE
                        t.errcode = u.errcode
                ),'{1}',t.date_a),'{2}',t.date_b)
            FROM
                t
            WHERE
                date_b IS NOT NULL
        ) di
    GROUP BY
        period;

编辑：

然而，Boneist的解决方案更好。

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