如何在 mql4 中创建二维数组？我使用了以下代码

Question

我想创建一个行数和列数可变的二维数组。当然，行数和列数是在 EA 交易开始时确定的。我写的一部分代码如下，这样就报错了

'[' - 无效的索引值 Ae_1320_test.mq4 85 13

注：需要注意的是第85行第13列指的是矩阵A的第二个索引。A[](第13列:[)]

非常感谢指导我的亲爱的朋友们

//+------------------------------------------------------------------+
//|                                                        
//|                        Copyright 2021, MetaQuotes Software Corp. |
//|                                             https://www.mql5.com |
//+------------------------------------------------------------------+
#property copyright "Copyright 2021, MetaQuotes Software Corp."
#property link      "https://www.mql5.com"
#property version   "1.00"
#property strict
//+------------------------------------------------------------------+
//| Expert initialization function                                   |
//+------------------------------------------------------------------+









double pt;
int OnInit() 
{
//---
//double pt;
//void init()
  {
 pt = Point;
  if (Digits == 3 || Digits == 5)
     {
      pt= 10*pt;
     }  
  }   
//---
   return(INIT_SUCCEEDED);
  }
//+------------------------------------------------------------------+
//| Expert deinitialization function                                 |
//+------------------------------------------------------------------+
void OnDeinit(const int reason)   
  {
//---

  }
//+------------------------------------------------------------------+
//| Expert tick function                                             |
//+------------------------------------------------------------------+

//---------------------------------------------------------------------- 

---

//------------------ Check Starting Of New Candle----------------------- 

---

//---------------------------------------------------------------------- 

---

//---------------------------------------------------------------------- 

---

//These are very frequent tasks that usually should be performed once 
per candle when a new bar starts.
//Coding such types of behavior is not difficult and only requires a few 
lines of code. You can see the actual code example below.
// Creating a variable to store the time when a new candle start.
// Populating the variable with the current server time.
datetime NewCandleTime = TimeCurrent();

// Creating a boolean function that returns:
// True, if this is a new candle;
// False if this candle isn't new.
// Remember that the function returns true every time you initialize the 
script.
// For example, when you load the indicator or EA to the chart or when 
you switch timeframes.
bool IsNewCandle()
{
   // If the time of the candle when the function ran last
   // is the same as the time this candle started,
   // return false, because it is not a new candle.
   if (NewCandleTime == iTime(Symbol(), 0, 0)) return false;

   // Otherwise, it is a new candle and we need to return true.
   else
   {
      // If it is a new candle, then we store the new value.
      NewCandleTime = iTime(Symbol(), 0, 0);
      return true;
   }
}

extern int m=30; 
extern  int n=5;
  int i,j;
  double b[];
  double A[][];
  double PivotColumn[];
  int Base_Idx[];



void OnTick()
{


  for (int i=0; m-1; i++)
    {
 for (int j=0; n;j++)
       { 
        A[i][j]=0;
       }  
    }
//-------------- Matrix A ---------------------- 
  for (int i=0;m-1;i++)
   {
     A[i][0]= i+2;
     A[i][1]= i+4;
     A[i][2]= i+6;
     A[i][3]= i+8;
     A[i][4]= i+10;
 
      b[i]= Close[i+1];
    }


  double tab[][];
    for (int i=0; m; i++)
      {
       for (int j=0; 2*m+n;j++)
         {
          tab[i][j]=0;
         }  
      }
    for (int i=0; m-1; i++)
      {
       for (int j=0; 2*m+n-1;j++)
         {
          tab[i][j]=A[i][j];
         }  
      }

       for(int i=0;m-1;i++)
        {
          tab[i][2*m+n]=b[i];
        }  

    for(int j=0;2*m+n-1;j++)
        {
          tab[m][j]=2;
        }


//+----------------------- Phase One Of SIMPLEX Method ----------------------------+


   for (int i=0; m-1; i++)
       {
        for (int j=0; 2*m+n;j++)
          {
       
            tab[m][j]=tab[m][j]-tab[i][j];
          }  
       } 
}