我有一个想要以其他格式保存的Json数据。
我的原始json数据是:
{
"info": {
"file1": {
"book1": {
"lines": {
"102:0": [
"102:0"
],
"105:4": [
"106:4"
],
"106:4": [
"107:1",
"108:1"
]
}
}
}
}
}
而且我想按以下方式映射它:
{
"name": "main",
"children": [
{
"name": "file1",
"children": [
{
"name": "book1",
"group": "1",
"lines": [
"102",
"102"
],
[
"105",
"106"
],
[
"106",
"107",
"108"
]
}
],
"group": 1,
}
],
"group": 0
}
但是书的数量和文件的数量将会更多。在这行代码中,“”内的第一部分(在:之前)被获取(“ 106:4”变为“ 106”)。键的数字为1,然后值的数字为列表([“ 106”,“ 107”,“ 108”])。
到目前为止,我尝试了以下代码:
const before = JSON.parse(JSON.stringify(json))
const filenames = Object.keys(before["info"]);
const after = {
name: 'main',
children: [],
group: 0,
lines: []
}
// I am not sure about this nested for loops
for(let x in filenames)
{
var booknames = Object.keys(before["info"][filenames[x]]);
for(let y in booknames){
var cf1 = Object.keys(before["info"][filenames[x]][booknames[y]]["lines"]);
var cf2 = Object.values(before["info"][filenames[x]][booknames[y]]["lines"]);
for (let z1 in cf1){
var cf = cf1[z1].split(":")[0];
}
for (let z2 in cf2){
var cfn = cf2[z2].split(":")[0]; // error: Uncaught TypeError: cf2[z2].split is not a function
}
}
}
const children = filenames.map((filename, idx) => {
const innerChildren = Object.keys(before["info"][filename]).map((n) => ({
name: n,
group: idx + 1,
}))
return ({
name: filename,
children: innerChildren,
group: idx + 1,
});
})
after.children = children;
console.log(after);
我试图弄清楚如何获得所需的值并正确映射。我认为我的for循环嵌套不是一个好主意。如果您能帮助我解决问题,我将不胜感激。
您可以使用reduce
方法并创建递归函数来构建嵌套结构。
const data = {"info":{"file1":{"book1":{"lines":{"102:0":["102:0"],"105:4":["106:4"],"106:4":["107:1","108:1"]}}}}}
function build(data) {
return Object.entries(data).reduce((r, [key, value]) => {
const obj = {}
if (key !== 'lines') {
obj.name = key;
obj.children = build(value)
} else {
if (!obj.lines) obj.lines = [];
Object.entries(value).forEach(([k, v]) => {
obj.lines.push([k, ...v].map(e => e.split(':').shift()))
})
}
r.push(obj)
return r;
}, [])
}
const result = build(data);
console.log(result);
我无法理解group
属性背后的逻辑,因此您可能需要为此添加更多信息,但是对于其余部分,您可以尝试使用这两个函数将对象递归转换为要获取的内容。
var a = JSON.parse('{"info":{"file1":{"book1":{"lines":{"102:0":["102:0"],"105:4":["106:4"],"106:4":["107:1","108:1"]}}}}}');
var transform = function (o) {
return Object.keys(o)
.map((k, ki, ko) => {
return {"name": k, "children": (k === "lines" ? parseLines(o[k]) : transform(o[k])) }
}
)
}
var parseLines = function (lines) {
return Object.keys(lines)
.map(v => [v.split(':')[0], ...(lines[v].map(l => l.split(":")[0]))])
}
console.log(JSON.stringify(transform(a)[0], null, 2));