我正在尝试使旧的gulpfile for launching processes现代化,但遇到问题。当我跑了一口气:
PS C:\Users\me\Desktop\_REPOS\gknode> gulp
[18:42:50] Using gulpfile ~\Desktop\_REPOS\gknode\gulpfile.js
[18:42:50] Task never defined: default
gulpfile.js
gulp=require('gulp')
//Because gulp.task(name, deps, func) was replaced by gulp.task(name, gulp.{series|parallel}(deps, func))
gulp.task('node-server-start', gulp.series(
function (cb) {spawn('node', ['nodeapi/nodeapi.js'], {stdio: 'inherit'}) }
)
);
gulp.task('ng-serve', gulp.series(
function (cb) {spawn('ng', ['serve'], {stdio: 'inherit'}) }
)
);
gulp.task('start', gulp.parallel(['ng-serve', 'node-server-start'], function () {console.log('both servers launched on localhost:4200')}));
任务树:
PS C:\Users\me\Desktop\_REPOS\gknode> gulp --tasks
[18:43:00] Tasks for ~\Desktop\_REPOS\gknode\gulpfile.js
[18:43:00] ├─┬ node-server-start
[18:43:00] │ └─┬ <series>
[18:43:00] │ └── <anonymous>
[18:43:00] ├─┬ ng-serve
[18:43:00] │ └─┬ <series>
[18:43:00] │ └── <anonymous>
[18:43:00] └─┬ start
[18:43:00] └─┬ <parallel>
[18:43:00] ├─┬ ng-serve
[18:43:00] │ └─┬ <series>
[18:43:00] │ └── <anonymous>
[18:43:00] ├─┬ node-server-start
[18:43:00] │ └─┬ <series>
[18:43:00] │ └── <anonymous>
[18:43:00] └── <anonymous>
我的问题是在启动任务结束时的匿名任务吗?
为了能够只运行gulp
,您需要指定一个名为default
的任务。其他一些观点:
gulp.series
中包装单个任务函数。gulp.parallel
期待一个任务函数列表(名称或匿名函数),而不是数组。最后一点可能没有必要让代码工作,但我已将它包含在下面的应该完成工作:
const gulp = require('gulp');
const { spawn } = require('child_process');
gulp.task('node-server-start', function(cb) {
const server = spawn('node', ['nodeapi/nodeapi.js'], { stdio: 'inherit' });
server.on('close', () => cb());
});
gulp.task('ng-serve', function(cb) {
const server = spawn(
/^win/.test(process.platform) ? 'ng.cmd' : 'ng',
['serve'],
{ stdio: 'inherit' }
);
server.on('close', () => cb());
});
gulp.task(
'start',
gulp.parallel('ng-serve', 'node-server-start', function(cb) {
console.log('both servers launched on localhost:4200');
cb();
})
);
gulp.task('default', gulp.series('start'));
更新:
更新了与平台无关的解决方案。