将颤振网格视图中最后一行项目居中

问题描述 投票:0回答:5

我有一个动态项目列表,正在输出到 mainAxisCount 为 2(2 列网格)的

GridView.count
构造函数中。如果列表长度为奇数,则最后一行将仅包含单个项目。我希望这个单个项目位于屏幕中央,而不是与第一列对齐。这可以吗?

flutter gridview flutter-layout
5个回答
2
投票

考虑到flutter_staggered_grid_view,有两个答案。虽然这是一个不错的包,但我认为它的功能比你想要的要多得多。

我提供了更多手动、自定义的实现。

import 'dart:math';

import 'package:flutter/rendering.dart';
import 'package:flutter/widgets.dart';

/// A [SliverGridLayout] that provide a way to customize the children geometry.
class SliverGridWithCustomGeometryLayout extends SliverGridRegularTileLayout {
  /// The builder for each child geometry.
  final SliverGridGeometry Function(
    int index,
    SliverGridRegularTileLayout layout,
  ) geometryBuilder;

  SliverGridWithCustomGeometryLayout({
    @required this.geometryBuilder,
    @required int crossAxisCount,
    @required double mainAxisStride,
    @required double crossAxisStride,
    @required double childMainAxisExtent,
    @required double childCrossAxisExtent,
    @required bool reverseCrossAxis,
  })  : assert(geometryBuilder != null),
        assert(crossAxisCount != null && crossAxisCount > 0),
        assert(mainAxisStride != null && mainAxisStride >= 0),
        assert(crossAxisStride != null && crossAxisStride >= 0),
        assert(childMainAxisExtent != null && childMainAxisExtent >= 0),
        assert(childCrossAxisExtent != null && childCrossAxisExtent >= 0),
        assert(reverseCrossAxis != null),
        super(
          crossAxisCount: crossAxisCount,
          mainAxisStride: mainAxisStride,
          crossAxisStride: crossAxisStride,
          childMainAxisExtent: childMainAxisExtent,
          childCrossAxisExtent: childCrossAxisExtent,
          reverseCrossAxis: reverseCrossAxis,
        );

  @override
  SliverGridGeometry getGeometryForChildIndex(int index) {
    return geometryBuilder(index, this);
  }
}

/// Creates grid layouts with a fixed number of tiles in the cross axis, such
/// that fhe last element, if the grid item count is odd, is centralized.
class SliverGridDelegateWithFixedCrossAxisCountAndCentralizedLastElement
    extends SliverGridDelegateWithFixedCrossAxisCount {
  /// The total number of itens in the layout.
  final int itemCount;

  SliverGridDelegateWithFixedCrossAxisCountAndCentralizedLastElement({
    @required this.itemCount,
    @required int crossAxisCount,
    double mainAxisSpacing = 0.0,
    double crossAxisSpacing = 0.0,
    double childAspectRatio = 1.0,
  })  : assert(itemCount != null && itemCount > 0),
        assert(crossAxisCount != null && crossAxisCount > 0),
        assert(mainAxisSpacing != null && mainAxisSpacing >= 0),
        assert(crossAxisSpacing != null && crossAxisSpacing >= 0),
        assert(childAspectRatio != null && childAspectRatio > 0),
        super(
          crossAxisCount: crossAxisCount,
          mainAxisSpacing: mainAxisSpacing,
          crossAxisSpacing: crossAxisSpacing,
          childAspectRatio: childAspectRatio,
        );

  bool _debugAssertIsValid() {
    assert(crossAxisCount > 0);
    assert(mainAxisSpacing >= 0.0);
    assert(crossAxisSpacing >= 0.0);
    assert(childAspectRatio > 0.0);
    return true;
  }

  @override
  SliverGridLayout getLayout(SliverConstraints constraints) {
    assert(_debugAssertIsValid());
    final usableCrossAxisExtent = max(
      0.0,
      constraints.crossAxisExtent - crossAxisSpacing * (crossAxisCount - 1),
    );
    final childCrossAxisExtent = usableCrossAxisExtent / crossAxisCount;
    final childMainAxisExtent = childCrossAxisExtent / childAspectRatio;
    return SliverGridWithCustomGeometryLayout(
      geometryBuilder: (index, layout) {
        return SliverGridGeometry(
          scrollOffset: (index ~/ crossAxisCount) * layout.mainAxisStride,
          crossAxisOffset: itemCount.isOdd && index == itemCount - 1
              ? layout.crossAxisStride / 2
              : _getOffsetFromStartInCrossAxis(index, layout),
          mainAxisExtent: childMainAxisExtent,
          crossAxisExtent: childCrossAxisExtent,
        );
      },
      crossAxisCount: crossAxisCount,
      mainAxisStride: childMainAxisExtent + mainAxisSpacing,
      crossAxisStride: childCrossAxisExtent + crossAxisSpacing,
      childMainAxisExtent: childMainAxisExtent,
      childCrossAxisExtent: childCrossAxisExtent,
      reverseCrossAxis: axisDirectionIsReversed(constraints.crossAxisDirection),
    );
  }

  double _getOffsetFromStartInCrossAxis(
    int index,
    SliverGridRegularTileLayout layout,
  ) {
    final crossAxisStart = (index % crossAxisCount) * layout.crossAxisStride;

    if (layout.reverseCrossAxis) {
      return crossAxisCount * layout.crossAxisStride -
          crossAxisStart -
          layout.childCrossAxisExtent -
          (layout.crossAxisStride - layout.childCrossAxisExtent);
    }
    return crossAxisStart;
  }
}

说明

稍微解释一下,这段代码的作用是它是

SliverGridLayout
的自定义实现,这是告诉 Flutter 如何在网格布局上定位子级的类类型。

这里比较重要的方法是

getGeometryForChildIndex
。该方法根据每个孩子的
index
确定其位置。但请注意,我们通过参数向我将要讨论的下一个类公开此方法。

我们实现的下一个类是

SliverGridDelegate
。我们必须进行自定义实现才能使用
SliverGridWithCustomGeometryLayout
,因为没有其他方法可以让委托使用特定的
SliverGridLayout
。这里我们使用参数
geometryBuilder
来委托它返回
SliverGridGeometry
的角色。

geometryBuilder
的实现是所有魔法发生的地方。它基本上是原始
SliverGridRegularTileLayout
方法的副本,但有一个更改。我们检查元素的索引是否为偶数以及是否也是最后一个。如果两项检查都通过,我们返回居中位置。否则,我们将返回它原本应有的位置。

要使用我们的解决方案,只需将其传递给

gridDelegate
上的
GridView
参数即可。示例:

GridView.builder(
    itemCount: 9,
    itemBuilder: (_, __) =>
        Container(width: 100, height: 100, color: Colors.red),
    gridDelegate:
        SliverGridDelegateWithFixedCrossAxisCountAndCentralizedLastElement(
            itemCount: checklist.sections.length(),
            crossAxisCount: 2,
            childAspectRatio: 0.825,
        ),
)

免责声明

这个解决方案没有经过详尽的测试,我把它发布在这里只是为了让人们知道如何制作它。但是,我在生产代码中使用它。如果我最终发现任何问题,我会在这里编辑。


1
投票

你试试下面的方法怎么样?

  1. 生成包含 2n 个项目的 GridView。
  2. 如果还有剩余项目,请为最后一项添加小部件。

0
投票

您可以使用 flutter_staggered_grid_view 包来实现此目的。

示例:

 StaggeredGridView.countBuilder(
  crossAxisCount: 4,
  itemCount: 8,
  itemBuilder: (BuildContext context, int index) => Container(
      color: Colors.green,
      child: Center(
        child: new CircleAvatar(
          backgroundColor: Colors.white,
          child: new Text('$index'),
        ),
      )),
  staggeredTileBuilder: (int index) =>
      StaggeredTile.count(2, index.isEven ? 2 : 1),
  mainAxisSpacing: 4.0,
  crossAxisSpacing: 4.0,
)
  1. 将最后一行的跨度计数返回为 1 内
    staggeredTileBuilder
  2. 返回
    itemBuilder
  3. 内最后一行的居中小部件

0
投票

您可以使用 StaggeredGridView

StaggeredGridView.countBuilder(
    crossAxisCount: 2,
    mainAxisSpacing: 4.0,
    crossAxisSpacing: 4.0,
    itemCount: totalCount,
    itemBuilder: (BuildContext context, int index) {
      return Center(
        child: Container(
          width: w,
          height: w,
          color: Colors.redAccent,
        ),
      );
    },
    staggeredTileBuilder: (int index) =>
        new StaggeredTile.count(index == totalCount-1 ? 2 : 1, 1),
)

0
投票
ListView.builder(
                              itemCount: (imagePaths.length / 3).ceil() +
                                  (imagePaths.length % 3 == 0
                                      ? 0
                                      : 1),
                              itemBuilder: (BuildContext context, int index) {
                                final int itemCountInRow = (index ==
                                            (imagePaths.length / 3).ceil() -
                                                1 &&
                                        imagePaths.length % 3 != 0)
                                    ? imagePaths.length % 3
                                    : 3; 
                                return Padding(
                                    padding: const EdgeInsets.all(8.0),
                                  child: Row(
                                    mainAxisAlignment: MainAxisAlignment
                                        .center, // Center the last row
                                    children: List.generate(itemCountInRow,
                                        (int subIndex) {
                                      final int actualIndex =
                                          index * 3 + subIndex;
                                      if (actualIndex >= imagePaths.length)
                                        return Container(); // Handle out-of-bounds access
                                      Map<String, dynamic> imageData =
                                          imagePaths[actualIndex];
                                      return card("Your widget"),
                                    }),
                                  ),
                                );
                              },
                            ),
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