我有一个问题。我已经尝试过,例如下面的示例。
import itertools
options = ['A', 'B', 'C']
true_or_false = ['true', 'false']
result1 = [f"{option} is " for option in options]
结果如下。
print(result1)
['A is ', 'B is ', 'C is ']
我想使用“ true_or_false”来产生这样的result2。
('A is true' 'B is true' 'C is true')
('A is true' 'B is true' 'C is false')
('A is true' 'B is false' 'C is true')
('A is true' 'B is false' 'C is false')
('A is false' 'B is true' 'C is true')
('A is false' 'B is true' 'C is false')
('A is false' 'B is false' 'C is true')
('A is false' 'B is false' 'C is false')
我认为它使用的是“组合”,但不起作用。
简单的嵌套循环可以输出您需要的内容
result2 = []
combinations = ['true','false']
for a in combinations:
for b in combinations:
for c in combinations:
result2.append(('A is ' + a, 'B is ' + b, 'C is ' + c))
[result2
将是一个元组列表:
[('A is true', 'B is true', 'C is true'),
('A is true', 'B is true', 'C is false'),
('A is true', 'B is false', 'C is true'),
('A is true', 'B is false', 'C is false'),
('A is false', 'B is true', 'C is true'),
('A is false', 'B is true', 'C is false'),
('A is false', 'B is false', 'C is true'),
('A is false', 'B is false', 'C is false')]