如何使用计算出的属性来格式化Out-GridView显示？

Question

下面的Powershell脚本非常适合显示Azure用户属性，除了需要格式化以删除公司域名的许可证列之外。

这是脚本。

#Import Module
If (!(Get-Module "*MSOnline*")) {Import-Module MSOnline}
If (!(Get-Module "*Exchange*")) {Import-Module $((Get-ChildItem -Path $($env:LOCALAPPDATA + "\Apps\2.0\") -Filter Microsoft.Exchange.Management.ExoPowershellModule.dll -Recurse).FullName | ?{ $_ -notmatch "_none_" } | select -First 1)}

#Set admin UPN
$UPN = '[email protected]'

#This connects to Azure Active Directory & Exchange Online
Connect-MsolService
$EXOSession = New-ExoPSSession -UserPrincipalName $UPN
Import-PSSession $EXOSession -DisableNameChecking -AllowClobber

$startsWith = @(
    'Test'
    'Sync_'
)

$endsWith = @(
    '365'
    '\$'
    'svc'
    'Sync'
    'user'
)

$pattern = '^({0})|({1})$' -f $($startsWith -join '|'), $($endsWith -join '|')

# Member Outputs for Microsoft.Online.Administration.User based on https://docs.microsoft.com/en-us/powershell/module/msonline/get-msoluser?view=azureadps-1.0
$allUsers = @()
$allUsers = Get-MsolUser -All -EnabledFilter EnabledOnly | Where-Object {
        ($_.UserPrincipalName -notmatch $pattern) -and
        ($_.UserPrincipalName -notlike '*#EXT#*') -and
        ($_.DisplayName -notmatch 'Admin|Calendar|Room|Prod|Account|Fax|Team|Office|Test|User')
} | Select-Object FirstName, 
    LastName, 
    UserPrincipalName,
    @{Label = 'SMTP Address(es)'; 
        Expression = { 
            If (( $_.UserPrincipalName -match 'onmicrosoft.com$')) {
              ($_.proxyAddresses | Where-Object { ($_ -like 'SMTP*') -and ($_ -like '*onmicrosoft.com') }) -replace 'smtp:' -join ';'
            } Else {
                ($_.proxyAddresses | Where-Object { ($_ -like 'SMTP*') -and ($_ -notlike '*onmicrosoft.com') }) -replace 'smtp:' -join ';'
            }
        } 
    },
    AlternateEmailAddresses, 
    UsageLocation, 
    isLicensed,
    Licenses,
    @{Label = 'License(s)'; 
        Expression = {
            ($_.Licenses | ForEach-Object { ($_.AccountSkuId | Where-Object { $_.AccountSkuId -like 'CorpFinanceLtd*' }) -replace 'CorpFinanceLtd:' } ) -join ';'
        }
    },
    PasswordNeverExpires, 
    BlockCredential

$allUsers | Out-GridView

我相信本节需要一些修改，但不确定如何做到这一点？

@{Label = 'License(s)'; 
    Expression = {
        ($_.Licenses | ForEach-Object { ($_.AccountSkuId | Where-Object { $_.AccountSkuId -like 'CorpFinanceLtd*' }) -replace 'CorpFinanceLtd:' } ) -join ';'
    }
},

默认的许可证列显示许可证信息，例如：{CorpFinanceLtd:MCOPSTNC, CorpFinanceLtd:ENTERPRISEPREMIUM, CorpFinanceLtd:EMSPREMIUM, CorpFinanceLtd:RIGHTSMANAGEMENT_ADHOC…}

因此，如何删除CorpFinanceLtd：前缀部分，这样可以得到更有意义的结果？

Answer 1

您将$_.AccountSkuId的value作为管道输入，但是继续在结果对象上寻找AccountSkuId属性-这是行不通的，因为它只是一个字符串。

您可以如下简化表达式：

@{
    Label = 'License(s)'; 
    Expression = {
        ($_.Licenses | ForEach-Object { $_.AccountSkuId  -replace '^CorpFinanceLtd:' } ) -join ';'
    }
},

^前面的CorpFinanceLtd:确保正则表达式引擎仅在字符串的开头匹配，不再需要通配符过滤器