无法解析为[保留类型]

Question

我从互联网复制了一个代码，并对其进行了一些更改。突然在第131行（下方）Cirlce cannot be resolved to a type中说出了什么情况？++++++++++++++++++++++++++++++++++++++++++++++++++++ +++++++++++++++++++++++++++++++++（对所有这些人表示抱歉，但是Stackoverflow神秘地说道：“看起来您的帖子大部分是代码；请添加更多详细信息。”在这里，您有“必要的”详细信息！

import java.io.*; 

interface Shape 
{ 
 // abstract method 
 void draw(); 
 double area(); 
 double volume();
} 

class Rectangle implements Shape  
{ 
    int length, width, height; 

 // constructor 
    Rectangle(int length, int width, int height) 
    { 
     this.length = length; 
     this.width = width; 
     this.height = height;
    } 

    @Override
    public void draw()  
    { 
     System.out.println("Rectangle has been drawn ");  
    } 

    @Override
    public double area()  
    { 
     return (double)(length*width); 

    } 

    public double volume()
    {
     return (double) (length*width*height);

    }  

class Circle implements Shape 
{ 

        double pi = 3.14; 
        int radius; 

        //constructor 
        Circle(int radius) 
        { 

            this.radius = radius; 
        } 

        @Override
        public void draw()  
        { 
            System.out.println("Circle has been drawn ");  
        } 

        @Override
        public double area()  
        { 

            return (double)((pi*radius*radius)/2); 

        } 

        public double volume()
        {
         return (double) 4/3*(Math.pow(radius,3));

        }  



} 

}
 class Demo  
{ 
     public static void main (String[] args)  
        { 

         // creating the Object of Rectangle class 
         // and using shape interface reference. 
         Shape rect = new Rectangle(2,3,4); 
         System.out.println("Area of rectangle: " + rect.area()+ "and volume is " + rect.volume()); 

         // creating the Objects of circle class 
         Shape circle = new Circle(2);     // LINE 131
         System.out.println("Area of circle: " + circle.area() + circle.volume()); 
        } 
} 

Answer 1

您在Circle内定义了Rectangle，但第131行不遵守此规定。