从高的Joomla PHP排序阵列以低[重复]

问题描述 投票:-1回答:1

这个问题已经在这里有一个答案:

我想排序从高分到低分的数组。

该查询写的的Joomla模块中,是这一个:

$authors = array();
    if (count($rows))
    {
        foreach ($rows as $row)
        {
            $author = JFactory::getUser($row->created_by);
            $author->link = JRoute::_(K2HelperRoute::getUserRoute($author->id));

            $query = "SELECT id, gender, description, image, url, `group`, plugins FROM #__k2_users WHERE userID=".(int)$author->id;
            $db->setQuery($query);
            $author->profile = $db->loadObject();

            if ($params->get('authorAvatar'))
            {
                $author->avatar = K2HelperUtilities::getAvatar($author->id, $author->email, $componentParams->get('userImageWidth'));
            }

            if (K2_JVERSION != '15')
            {
                $languageCheck = '';
                if ($application->getLanguageFilter())
                {
                    $languageTag = JFactory::getLanguage()->getTag();
                    $languageCheck = "AND i.language IN (".$db->Quote($languageTag).", ".$db->Quote('*').") AND c.language IN (".$db->Quote($languageTag).", ".$db->Quote('*').")";
                }
                $query = "SELECT i.*, c.alias as categoryalias FROM #__k2_items as i
                LEFT JOIN #__k2_categories c ON c.id = i.catid
                WHERE i.created_by = ".(int)$author->id."
                AND i.published = 1
                AND i.access IN(".implode(',', $user->getAuthorisedViewLevels()).")
                AND ( i.publish_up = ".$db->Quote($nullDate)." OR i.publish_up <= ".$db->Quote($now)." )
                AND ( i.publish_down = ".$db->Quote($nullDate)." OR i.publish_down >= ".$db->Quote($now)." )
                AND i.trash = 0 AND created_by_alias='' AND c.published = 1 AND c.access IN(".implode(',', $user->getAuthorisedViewLevels()).") AND c.trash = 0 {$languageCheck} ORDER BY created DESC";
            }
            else
            {
                $query = "SELECT i.*, c.alias as categoryalias FROM #__k2_items as i
                LEFT JOIN #__k2_categories c ON c.id = i.catid
                WHERE i.created_by = ".(int)$author->id."
                AND i.published = 1
                AND i.access <= {$aid}
                AND ( i.publish_up = ".$db->Quote($nullDate)." OR i.publish_up <= ".$db->Quote($now)." )
                AND ( i.publish_down = ".$db->Quote($nullDate)." OR i.publish_down >= ".$db->Quote($now)." )
                AND i.trash = 0 AND created_by_alias='' AND c.published = 1 AND c.access <= {$aid} AND c.trash = 0 ORDER BY created DESC";
            }

            $db->setQuery($query, 0, 1);
            $author->latest = $db->loadObject();
            $author->latest->id = (int)$author->latest->id;
            $author->latest->link = urldecode(JRoute::_(K2HelperRoute::getItemRoute($author->latest->id.':'.urlencode($author->latest->alias), $author->latest->catid.':'.urlencode($author->latest->categoryalias))));

            $query = "SELECT COUNT(*) FROM #__k2_comments WHERE published=1 AND itemID={$author->latest->id}";
            $db->setQuery($query);
            $author->latest->numOfComments = $db->loadResult();

            if ($params->get('authorItemsCounter'))
            {
                if (K2_JVERSION != '15')
                {
                    $languageCheck = '';
                    if ($application->getLanguageFilter())
                    {
                        $languageTag = JFactory::getLanguage()->getTag();
                        $languageCheck = "AND language IN (".$db->Quote($languageTag).", ".$db->Quote('*').")";
                    }
                    $query = "SELECT COUNT(*) FROM #__k2_items  WHERE {$where} published=1 AND ( publish_up = ".$db->Quote($nullDate)." OR publish_up <= ".$db->Quote($now)." ) AND ( publish_down = ".$db->Quote($nullDate)." OR publish_down >= ".$db->Quote($now)." ) AND trash=0 AND access IN(".implode(',', $user->getAuthorisedViewLevels()).") AND created_by_alias='' AND created_by={$row->created_by} {$languageCheck} AND EXISTS (SELECT * FROM #__k2_categories WHERE id= #__k2_items.catid AND published=1 AND trash=0 AND access IN(".implode(',', $user->getAuthorisedViewLevels()).") {$languageCheck} )";
                }
                else
                {
                    $query = "SELECT COUNT(*) FROM #__k2_items  WHERE {$where} published=1 AND ( publish_up = ".$db->Quote($nullDate)." OR publish_up <= ".$db->Quote($now)." ) AND ( publish_down = ".$db->Quote($nullDate)." OR publish_down >= ".$db->Quote($now)." ) AND trash=0 AND access<={$aid} AND created_by_alias='' AND created_by={$row->created_by} AND EXISTS (SELECT * FROM #__k2_categories WHERE id= #__k2_items.catid AND published=1 AND trash=0 AND access<={$aid} ) ";
                }
                $db->setQuery($query);
                $numofitems = $db->loadResult();
                $author->items = $numofitems;
            }

            $authors[] = $author;

        }
    }


    return $authors;
}

然后将结果传递给这些变量,最后返回authors表。这表我想排序从高分到低分。我已经尝试了PHP功能,但他们都不来工作。

如果查询检索别的东西超出了项目计数器,并设置为关键我不能肯定。但我已经试过功能,如arsort这是由价值而不是关键排序。

$db->setQuery($query);
$numofitems = $db->loadResult();
$author->items = $numofitems;
$authors[] = $author;
arsort($authors);

任何想法表示赞赏

谢谢

php sorting joomla
1个回答
1
投票

一般数据库查询可以通过指定顺序的排序

$query->order('my_table.my_column desc')

如果你整理一个PHP数组,并要求自定义排序标准,您可以使用自己的分类标准与usort。例如:

// Your comparison function:

function myComparer($object1, $object2)
{
    if ($object1->item == $object2->item) {
       return 0;
    }

    return ($object1->item < $object2-item) ? -1 : 1;
}

// Sort the array in place

usort($authors, 'myComparer');

注意:您可以通过简单地交换比较返回值反转排序顺序:

return ($object1->itemCount < $object2-itemCount) ? 1 : -1;
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